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Anika [276]
3 years ago
5

What is the solution to log (9x)-log2^3= 3?

Mathematics
2 answers:
RoseWind [281]3 years ago
5 0

Answer:

  1. b

Step-by-step explanation: i got it right on edg

olga_2 [115]3 years ago
3 0

For this case we have that by definition of properties logarithm is met:

log_ {b} (x) -log_ {b} (y) = log_ {b} (\frac {x} {y})

So, rewriting the expression we have:

log (\frac {9x} {2 ^ 3}) = 3\\log (\frac {9x} {8}) = 3

By definition of logarithm we have to:

log_ {b} (x) = yis equivalent tob ^ y = x

So:

10 ^ 3 = \frac {9x} {8}\\9x = 8 * 10 ^ 3\\9x = 8 * 1000\\9x = 8000\\x = \frac {8000} {9}

ANswer:

x = \frac {8000} {9}

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