Question

What is the solution to log (9x)-log2^3= 3?

Answer 1

Answer:

1. b

Step-by-step explanation: i got it right on edg

Answer 2

For this case we have that by definition of properties logarithm is met:

$log_ {b} (x) -log_ {b} (y) = log_ {b} (\frac {x} {y})$

So, rewriting the expression we have:

$log (\frac {9x} {2 ^ 3}) = 3\\log (\frac {9x} {8}) = 3$

By definition of logarithm we have to:

$log_ {b} (x) = y$is equivalent to$b ^ y = x$

So:

$10 ^ 3 = \frac {9x} {8}\\9x = 8 * 10 ^ 3\\9x = 8 * 1000\\9x = 8000\\x = \frac {8000} {9}$

ANswer:

$x = \frac {8000} {9}$