Ask question

Ask question

All categories

3 years ago

14

An observer spots a plane flying at a 42 degree angle to his horizontal line of sight. If the plane is flying at an altitude of

15,000 ft, what is the distance (x) from the plane (P) to the observer (O)

1 answer:

Natalija [7]3 years ago

6 0

check the picture below.

make sure your calculator is in Degree mode.

You might be interested in

63.09 ÷ .00008<br><br>No rush on this, but if you know please respond, it will be appreciated.

mart [117]

Answer is 788, 625. Hope this helped!

3 0

3 years ago

In basketball, some baskets are worth two points. Others are worth three points. In one game, the ratio of three-point basket

Alex787 [66]

The number of three-point tries is 36.

<h3>What are ratios?</h3>

Ratio expresses the relationship between two or more numbers. It shows the frequency of the number of times that one value is contained within other value(s).

<h3 /><h3>What is the number of three point tries?</h3>

The first step is to determine the total number of tries and baskets: (27 X 7)/3 = 63

Number of three-point tries = (4/7) x 63 = 36

To learn more about ratios, please check: brainly.com/question/25927869

4 0

2 years ago

What is x+y <3 (0,0)

larisa [96]

The expression is a bit invalid. You can't add variables by variables.

3 0

3 years ago

First, and correct answer gets brainliest, also worth 50 points

pishuonlain [190]

One angle be x

other is 2x-6

ATQ

$\\ \sf\longmapsto x+2x-6=90$

$\\ \sf\longmapsto 3x-6=90$

$\\ \sf\longmapsto 3x=96$

$\\ \sf\longmapsto x=32$

$\\ \sf\longmapsto 2x-6=2(32)-6=58°$

4 0

2 years ago

Read 2 more answers

Pls solve the simultaneous equation in the attachment.

siniylev [52]

Answer:

Part a) The solution is the ordered pair (6,10)

Part b) The solutions are the ordered pairs (7,3) and (15,1.4)

Step-by-step explanation:

Part a) we have

$\frac{x}{2}-\frac{y}{5}=1$ ----> equation A

$y-\frac{x}{3}=8$ ----> equation B

Multiply equation A by 10 both sides to remove the fractions

$5x-2y=10$ ----> equation C

isolate the variable y in equation B

$y=\frac{x}{3}+8$ ----> equation D

we have the system of equations

$5x-2y=10$ ----> equation C

$y=\frac{x}{3}+8$ ----> equation D

Solve the system by substitution

substitute equation D in equation C

$5x-2(\frac{x}{3}+8)=10$

solve for x

$5x-\frac{2x}{3}-16=10$

Multiply by 3 both sides

$15x-2x-48=30$

$15x-2x=48+30$

Combine like terms

$13x=78$

$x=6$

<em>Find the value of y</em>

$y=\frac{x}{3}+8$

$y=\frac{6}{3}+8$

$y=10$

The solution is the ordered pair (6,10)

Part b) we have

$xy=21$ ---> equation A

$x+5y=22$ ----> equation B

isolate the variable x in the equation B

$x=22-5y$ ----> equation C

substitute equation C in equation A

$(22-5y)y=21$

solve for y

$22y-5y^2=21$

$5y^2-22y+21=0$

Solve the quadratic equation by graphing

The solutions are y=1.4, y=3

see the attached figure

<em>Find the values of x</em>

For y=1.4

$x=22-5(1.4)=15$

For y=3

$x=22-5(3)=7$

therefore

The solutions are the ordered pairs (7,3) and (15,1.4)

3 0

3 years ago