A hatchling turtle has a shell with a 1 inch diameter.

GarryVolchara [31]

It maybe be B if i am wrong i am sorry.

3 0

3 years ago

3.16 SAT scores: SAT scores (out of 2400) are distributed normally with a mean of 1490 and a standard deviation of 295. Suppose

AURORKA [14]

Answer:

0.2333 = 23.33% probability this student's score will be at least 2100.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution, and conditional probability.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

SAT scores (out of 2400) are distributed normally with a mean of 1490 and a standard deviation of 295.

This means that $\mu = 1490, \sigma = 295$

In this question:

Event A: Student was recognized.

Event B: Student scored at least 2100.

Probability of a student being recognized:

Probability of scoring at least 1900, which is 1 subtracted by the pvalue of Z when X = 1900. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{1900 - 1490}{295}$

$Z = 1.39$

$Z = 1.39$ has a pvalue of 0.9177

1 - 0.9177 = 0.0823

This means that $P(A) = 0.0823$

Probability of a student being recognized and scoring at least 2100:

Intersection between at least 1900 and at least 2100 is at least 2100, so this is 1 subtracted by the pvalue of Z when X = 2100.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{2100 - 1490}{295}$

$Z = 2.07$

$Z = 2.07$ has a pvalue of 0.9808

This means that $P(A \cap B) = 1 - 0.9808 = 0.0192$

What is the probability this student's score will be at least 2100?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0192}{0.0823} = 0.2333$

0.2333 = 23.33% probability this student's score will be at least 2100.

4 0

3 years ago

Rachel jogged a long a trail that was of 1/8 mile long . she jogged the 8 times. how meny miles trail did Rachel jog in all

galben [10]

It's 1 mile. She ran an 8th if an mile. If the ran 1/8 of a mile 8 times, it adds up to 1 mile.

5 0

3 years ago

3 drinks and 2 hot dog costs 7.70 and 2 drinks and one hot dog is 4.55 system of equation on drink and one hot dog to the neares

Pepsi [2]

Answer:

Drink = 1.4

Hot dog = 1.75

x + y = 3.15

Step-by-step explanation:

Let drink = x ; hot dog = y

3x + 2y = 7.70 - - (1)

2x + y = 4.55 - - - (2)

From (2)

y = 4.55 - 2x - - - (3)

Put y = 4.55 - 2x in (1)

3x + 2(4.55 - 2x) = 7.70

3x + 9.1 - 4x = 7.70

-x = 7.7 - 9.1

-x = - 1.4

x = 1.4

Put x = 1.4 in (3)

y = 4.55 - 2(1.4)

y = 4.55 - 2.8

y = 1.75

Drink = 1.4

Hot dog = 1.75

x + y = 3.15

7 0

3 years ago

I need help on this. please show your work.

ehidna [41]

The order of the size of angles is related to the order of the length that is opposite to that angle.

angle A is across from the smallest side, 2.4.
angle C is across from the middle side, 3.2
angle B is across from the longest side, 5.5

if you think about it, angle B has to be widest angle for it to accommodate the longest length (longer it is, the more you have to open). anlge A has to be the smallest angle for it to correspond with the smallest length

The order of smallest to largest is ∠A, ∠C, ∠B

8 0

4 years ago