Answer:
none
Step-by-step explanation:
We are given a triangle ABC with ∠A = 30°, sides a = 4 and b = 10.
According to the 'Law of Sines- Ambiguous Case', we have,
If a < b×sinA, then no triangle is possible.
If a = b×sinA, only one triangle is possible
If a > b×sinA, two triangles are possible.
So, we have,
b×sinA = 10 × sin30 = 10 × 0.5 = 5.
Now, as
4 = a < bsinA = 5.
We get, according to the rule, no triangle is possible.
It would be b because a^2+b^2=c^2 so in this case 5^2+8^2=c^2
Answer:
(y - 4)(y + 4)
Step-by-step explanation:
y² - 16 ← is a difference of squares
Since y² and 16 are both squares separated by a difference , that is minus
A difference of squares factors as
y² - 16
= y² - 4²
= (y - 4)(y + 4)
Answer:
It helps in common sense
Step-by-step explanation:
