Answer:
The total amount that all three friends have = $258
Step-by-step explanation:
Three friends: let their initial money be Ami's money =A, Jan = B, Toy = C
Toy started with $36 and ended with same amount
C = $36
After Ami gives, She is left with= A-x
Jan becomes= 2B
Toy becomes= 2C = 2×36 = 72
After Jan gives, Jan is left with = 2B-y
Ami now has = 2(A-x)
Toy now has = 2(72) = 144
After Toy gives, Toy is left with= 144-z
Ami now has = 2(2)(A-x) = 4(A-x)
Jan now has = 2(2B-y)
Since Toy is left with $36 at the end:
36 = 144-z
z = 144-36 = 108
So Toy spent $108 to double his two other friend's money
Both Amy and Jan had $108 in total when Toy had $144
Difference between the deductions across = $108
The total amount that all three friends have = 144+108
The total amount that all three friends have= $258
![z=2x^4+8x \\ dz=(8x^3+8)\ dx=8(x^3+1)\ dx \\ \int\limits^0_{-1} {(2x^4+8x)^3*(4x^3+4)} \, dx =4* \int\limits^0_{-6} { \dfrac{z^3}{2}} \, dz \\ = 2* \left[\begin{array}{ccc} \dfrac{z^4}{4}\end{array}\right] ^0_{-6}= \left[\begin{array}{ccc} \dfrac{z^4}{2}\end{array}\right] ^0_{-6}=0-648=-648](https://tex.z-dn.net/?f=%20z%3D2x%5E4%2B8x%20%5C%5C%0Adz%3D%288x%5E3%2B8%29%5C%20dx%3D8%28x%5E3%2B1%29%5C%20dx%20%5C%5C%0A%0A%20%5Cint%5Climits%5E0_%7B-1%7D%20%7B%282x%5E4%2B8x%29%5E3%2A%284x%5E3%2B4%29%7D%20%5C%2C%20dx%20%3D4%2A%20%5Cint%5Climits%5E0_%7B-6%7D%20%7B%20%5Cdfrac%7Bz%5E3%7D%7B2%7D%7D%20%5C%2C%20dz%20%5C%5C%0A%3D%202%2A%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%20%5Cdfrac%7Bz%5E4%7D%7B4%7D%5Cend%7Barray%7D%5Cright%5D%20%5E0_%7B-6%7D%3D%0A%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%20%5Cdfrac%7Bz%5E4%7D%7B2%7D%5Cend%7Barray%7D%5Cright%5D%20%5E0_%7B-6%7D%3D0-648%3D-648)