Answer:
A gasoline tank for a certain car is designed to hold 14.0 gal of gas.
a)What is the probability that a randomly selected tank will hold at most 13.7 gal?
We are supposed to find 
Refer the z table for p value
p value = 0.0668
So, 
The probability that a randomly selected tank will hold at most 13.7 gal is 0.0668
b)What is the probability that a randomly selected tank will hold between 13.4 and 14.3 gal?
We are supposed to find 
P(x<13.4)=P(z<-3)= 0.0013
P(x<14.3)= 0.9332
The probability that a randomly selected tank will hold between 13.4 and 14.3 gal is 0.9319
(c) If two such tanks are independently selected, what is the probability that both hold at most 14 gal?
We are supposed to find 
Refer the z table for p value
p value = 0.5
So, 
Two such tanks are independently selected, the probability that both hold at most 14 gal = 0.5 * 0.5 = 0.25
Hence If two such tanks are independently selected, the probability that both hold at most 14 gal is 0.25
Find how many cars she can wash in one day:
95 cars / 5 days = 19 cars per day.
Now multiply by 11 days:
19 cars per day x 11 days = 209 total cars.
Answer:
radius ≈ 15.5
Step-by-step explanation:
the radius is RS
the angle between a tangent and the radius at the point of contact is 90°
then Δ RST is a right triangle
using Pythagoras' identity in the right triangle.
the square on the hypotenuse is equal to the sum of the squares on the other 2 sides , then
RS² + ST² = RT² ( substitute values )
RS² + 7² = 17²
RS² + 49 = 289 ( subtract 49 from both sides )
RS² = 240 ( take square root of both sides )
RS = 
≈ 15.5 ( to 1 dec. place )
0.98867. there are eight numbers, to get from one number to another use this
Given:
Diameter of outer circle = 20 inches.
We need to find the Area of the outer circle to get the radius of the inner circle.
Area = πr²
Outer circle Area = 3.14 * (10in)² = 314 in²
314 in² * 64% probability = 200.96 in² Area of the inner circle.
200.96 in² = 3.14 * r²
200.96 in² / 3.14 = r²
64 in² = r²
√64 in² = √r²
8 in = r
radius of inner circle is 8 inches.
