<span>Evaluate 3x<span> at </span><span>x = –2, –1, 0, 1, </span>and<span> 2</span>.</span><span>To find the answer, I need to plug in the given values for x, and simplify:</span><span><span>Given </span><span>f(x) = 3</span><span>–x</span><span>, evaluate </span><span>f(–2), f(–1), f(0), f(1), </span>and<span> f(2)</span>.</span><span>To find the answer, I need to plug in the given values for x, and simplify:</span>
Take another look at the values I came up with: they were precisely reversed between the two T-charts. Remember that negative exponents<span> mean that you have to flip the base to the other side of the fraction line. This means that </span>3<span>–x</span><span> may also be written as </span><span>(<span> 1</span>/3 )</span>x, by taking the "minus" in the exponent and using it to flip the base "3". With this in mind, you should be able to predict the values for the following problem: Copyright © Elizabeth Stapel 2002-2011 All Rights Reserved
<span><span>Given </span><span>g(x) = (<span> 1</span>/3 )</span>x<span>, evaluate for </span><span>x = –2, –1, 0, 1, </span>and<span> 2</span>.</span><span><span> </span></span><span>Plug in the given values for x, and simplify:</span>
This exercise points out two things. First, you really do need to be good with exponents in order to do exponentials (so review the topic, if necessary), and, second, exponential decay (getting smaller and smaller by half (or a third, or...) at each step) is just like exponential growth, except that either the exponent is "negative" (the "–x" in "3<span>–x</span><span>") or else the base is between </span>0<span> and </span>1<span> (the </span><span>"1/3"</span><span> in "</span><span>(<span> 1</span>/3 )</span>x").
It will likely be necessary for you to be able to just look at an equation or an expression or a graph and correctly identify which type of change it represents, growth or decay, so go back and study the above examples, if you're not sure of what is going on here.
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<span>To be thorough, since </span>3x<span> models growth:</span> <span> </span></span><span>
<span>...and since </span>3<span>–x</span><span> and </span><span>(<span> 1</span>/3 )</span>x<span> model decay:</span> </span></span>
