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OLga [1]
3 years ago
11

Alexis has a piece of red paper that is 4 centimeters wide. Its length is twice its width. She glues a piece of blue paper on to

p of the red piece measuring 3 centimeters by 7 centimeters. How many square centimeters of red paper will be visible on top?
Mathematics
2 answers:
Lisa [10]3 years ago
4 0
(4x8) - (3x7) will give you what is showing of the red paper
cestrela7 [59]3 years ago
3 0

It is given:Alexis has a piece of red paper that is 4 centimeters wide. Its length is twice its width .If  length is 4cm then width = 4x2= 8cm.

Area of red paper= length x width = 4x8=32 square cm.

Alexis glues a piece of blue paper on top of the red piece measuring 3 centimeters by 7 centimeters.

Area of blue paper= 3x7=21 square cm.

Area of  red paper  that will be visible on top =32-21= 11 square cm.

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madreJ [45]
Compare the areas of the 2 different pieces of paper.

For the circle, the area is A=pi * r^2, which works out to A = pi(5 inches)^2.

For the square, the area is A = s^2, where is the side length, which here is 11 inches.

Finish these calculations, and then compare your two areas.  Which is the larger?
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2 years ago
Identify the equation for the parabola with vertex (0, 0) and directrix x = 2.5.
GREYUIT [131]

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Step-by-step explanation:

8 0
3 years ago
What statement is true?
givi [52]

Answer:

\frac{18}{32}>\frac{16}{32}

Step-by-step explanation:

We need to find which statements are true.

Solution to find the same we will solve each statement and will conclude the same.

1.  \frac{14}{21}>\frac{17}{24}

Now On solving we get;

\frac{14}{21} = 0.66

\frac{17}{24}=0.70

So we can see that 0.70 > 0.66

Hence The given statement is False.

2. \frac{18}{32}>\frac{16}{32}

Now On solving we get;

\frac{18}{32}=0.5625

\frac{16}{32}= 0.5

So we can see that 0.5625 > 0.5

Hence The given statement is True.

3.  \frac{20}{15}

Now On solving we get;

\frac{20}{15} = 1.33

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So we can see that 1.33 > 1.2

Hence The given statement is False.

4.  \frac{29}{35}

Now On solving we get;

\frac{29}{35}= 0.82

\frac{20}{30}= 0.66

So we can see that 0.82 > 0.66

Hence The given statement is False.

7 0
3 years ago
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stich3 [128]
Do you have a picture would probably make more sense if you added one
4 0
2 years ago
The ratio of one lengths of corresponding sides of two similar hexagons is 4:7. Find the ratios of their PERIMETERS.
faust18 [17]

9514 1404 393

Answer:

  4 : 7

Step-by-step explanation:

The ratio of perimeters is exactly the same as the ratio of side lengths. Multiplying each side by 7/4 multiplies the sum of the sides by 7/4.

The ratio of perimeters is 4 : 7.

3 0
2 years ago
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