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3 years ago

8

Please I need help with this I don't understand my teacher gave us a valentines day assignment like what the heck I seriously do

n't get it I will mark you as brainliest if you answer correctly pls and ty aaaaa

1 answer:

Helen [10]3 years ago

6 0

Answer:

A) 5x = y

B) $2x \leq 100$

Step-by-step explanation:

A is 5x = y because there are 5 pink hearts per the number of boxes (x) bought.

B uses the equation 2x is less than or equal to 100 because the teacher is spending 2 dollars per kid and can spend a maximum of 100.

The graph for this is attached.

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The table below shows some values of a linear function. What are the missing values

Black_prince [1.1K]

Answer:

C

Step-by-step explanation:

to get to 18 from 15, you add three.

You keep adding three to every number for the y values since it it a linear function. The x values went up by 1 and the y values went up by 3.

5 0

3 years ago

For Part A, my answer was 435 since I multiplied 5 x 87 = 435.

maksim [4K]

Answer:

a. 36.25 ft

b. 45 ft

Step-by-step explanation:

GIVE YOUR ANSWER IN FEET !!! as the problem statement says.

not in inches. when you use the scale factor with inches, you get inches as result. then you need to convert them to feet.

how many inches in 1 ft ?

12 !

so, you need to divide your results by 12 to get the feet.

3 0

3 years ago

Please help math questions <br> put number with answers please

natita [175]

Answer:

See below for answers

Step-by-step explanation:

<u>Problem 1</u>

<u /> $\frac{1}{sin\theta}=2cos\theta\: ; \: 0\leq\theta < 2\pi\\\\1=2sin\theta cos\theta\\\\1=sin2\theta\\\\\frac{\pi}{2}+2\pi n=2\theta\\ \\\frac{\pi}{4}+\pi n=\theta\\ \\\theta=\bigr\{\frac{\pi}{4},\frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}\bigr\}$

Therefore, the second option is correct.

<u>Problem 2</u>

<u /> $cos(2x)+1=sin(x)+2\:;\: 0\leq x < 2\pi\\\\1-2sin^2x+1=sin(x)+2\\\\-2sin^2x=sin(x)\\\\0=2sin^2x+sinx\\\\0=sinx(2sinx+1)$

$0=sinx\\\\x=\pi n\\\\x=0,\pi$

$0=2sinx+1\\\\-1=2sinx\\\\-\frac{1}{2}=sinx\\ \\x=\frac{7\pi}{6}+2\pi n,\frac{11\pi}{6}+2\pi n\\\\x=\frac{7\pi}{6},\frac{11\pi}{6}$

Therefore, the solution set is $x=\bigr\{0,\pi,\frac{7\pi}{6},\frac{11\pi}{6}\bigr\}$ , making the second option correct.

<u>Problem 3</u>

<u /> $2cos^2x=-cosx\: ;\: 0^\circ\leq x < 360^\circ\\\\2cos^2x+cosx=0\\\\cosx(2cosx+1)=0$

$cosx=0\\\\x=\frac{\pi}{2}+\pi n\\ \\x=90^\circ+180n^\circ\\\\x=90^\circ,270^\circ$

$2cosx+1=0\\\\2cosx=-1\\\\cosx=-\frac{1}{2}\\\\x=\frac{2\pi}{3}+2\pi n,\frac{4\pi}{3}+2\pi n\\ \\x=120^\circ+360n^\circ,240^\circ+360n^\circ\\\\x=120^\circ,240^\circ$

Therefore, the solution set is $x=\bigr\{90^\circ,120^\circ,240^\circ,270^\circ\bigr\}$ , making the fourth option correct

7 0

3 years ago

Yis inversely proportional to the square of x.

PtichkaEL [24]

Answer:

(a) $y = \frac{4}{x^2}$

(b) $x = \frac{2}{5}$

Step-by-step explanation:

Given

Variation: Inverse proportional.

This is represented as:

$y\ \alpha\ \frac{1}{x^2}$

See attachment for table

Solving (a):

First convert variation to equation

$y = k\frac{1}{x^2}$

From the table:

$(x,y) = (1,4)$

So, we have:

$4 = k * \frac{1}{1^2}$

$4 = k * \frac{1}{1}$

$4 = k * 1$

$4 = k$

$k = 4$

Substitute 4 for k in $y = k\frac{1}{x^2}$

$y = 4 * \frac{1}{x^2}$

$y = \frac{4}{x^2}$

Solving (b): x when y = 25.

Substitute 25 for y in $y = \frac{4}{x^2}$

$25 = \frac{4}{x^2}$

Cross Multiply

$25 * x^2 = 4$

Divide through by 25

$x^2 = \frac{4}{25}$

Take positive square roots of both sides

$x = \sqrt{\frac{4}{25}$

$x = \frac{2}{5}$

4 0

3 years ago

Someone help please answer question 1

vampirchik [111]

Answer:

Reflection in line x=1

Step-by-step explanation:

If you draw a line of all values where X = 1. It forms a line between the 2 shapes and by reflecting in that line, you will get Shape B from shape A

8 0

3 years ago