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alekssr [168]
3 years ago
12

What is the maximum value of the feasible regions if P = 120x + 100y

Mathematics
1 answer:
harkovskaia [24]3 years ago
5 0

Answer:

The maximum value of the feasible regions is P=500

Step-by-step explanation:

we know that

To find out the maximum value of the feasible regions, substitute the value of x and the value of y of each region in the objective function P and then compare the results

we have

P=120x+100y

Region 1 (0,5)

For x=0, y=5

substitute

P=120(0)+100(5)=500

Region 2 (0,4)

For x=0, y=4

substitute

P=120(0)+100(4)=400

Region 3 (4,0)

For x=4, y=0

substitute

P=120(4)+100(0)=480

Region 4 (3,0)

For x=3, y=0

substitute

P=120(3)+100(0)=360

Compare

The maximum value of the feasible regions is P=500

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Step-by-step explanation:

\boxed{\textsf{If }y=x^n,\: \textsf{then }\dfrac{\text{d}y}{\text{d}x}=nx^{n-1}}

<u>Given equation</u>:

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Learn more about differentiation here:

brainly.com/question/27958412

brainly.com/question/26488862

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Step-by-step explanation:

Hope it helps

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