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butalik [34]
4 years ago
6

Gracie read 150 pages of a book she got for her birthday the book is 227 pages long whats the right equation

Mathematics
1 answer:
Yakvenalex [24]4 years ago
7 0
Are there options or when is her birthday what is the rest of the problem
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Chelsea drew two parallel lines KL and MN intersected by a transversal PQ, as shown below:
Ilia_Sergeevich [38]

Answer:

The correct answer choice would be:

C (Same-Side Interior Angles Theorem)

Hope this helps! :)

5 0
3 years ago
Read 2 more answers
The radioactive isotope radium has a half-life of 1,600 years. The mass of a 100-gram sample of radium will be______ grams after
Olenka [21]
To solve this we are going to use the half life equation N(t)=N_{0} e^{( \frac{-0.693t}{t _{1/2} }) }
Where:
N_{0} is the initial sample
t is the time in years
t_{1/2} is the half life of the substance
N(t) is the remainder quantity after t years 

From the problem we know that:
N_{0} =100
t=200
t_{1/2} =1600

Lets replace those values in our equation to find N(t):
N(200) =100e^{( \frac{(-0.693)(200)}{1600}) }
N(200)=100e^{( \frac{-138.6}{1600} )}
N(200)=100e^{-0.086625}
N(200)=91.7

We can conclude that after 1600 years of radioactive decay, the mass of the 100-gram sample will be 91.7 grams.

8 0
3 years ago
A pizzeria sells a round pizza with a diameter of 16 inches. Another pizzeria sells a large square pizza with a side length of 1
ankoles [38]

Answer:

pizzeria1

Step-by-step explanation:

Given data

pizzeria1

Diameter=16in

Radius= 16/2= 8in

Area= πr^2

Area= 3.132*8^2

Area= 201.09 in^2

pizzeria2

Diameter=15in

Radius= 15/2= 7.5in

Area= πr^2

Area= 3.132*7.5^2

Area= 176.74n^2

4 0
3 years ago
**hint** Find the hypotenuse and then subtract that from the distance he actually traveled.
icang [17]

Answer:

10 miles

Step-by-step explanation:

5 0
3 years ago
HELP When 2((Three-fifths x + 2 and three-fourths y minus one-fourth x minus 1 and one-half y + 3)) is simplified, what is the r
lesya692 [45]

Answer:

<h2> StartFraction 7 over 10 EndFraction x + 2 and one-half y + 6</h2>

Step-by-step explanation:

Given the expression 2(\frac{3x}{5}+2\frac{3y}{4}-\frac{x}{4}-1 \frac{1}{2}y+3)

To simplify the expression, we need to first collect the like terms of the functions in parentheses as shown;

= 2(\frac{3x}{5}-\frac{x}{4}-1 \frac{1}{2}y+2\frac{3}{4}y+3)\\= 2(\frac{3x}{5}-\frac{x}{4}- \frac{3}{2}y+\frac{11}{4}y+3)\\

Then we find the LCM of the resulting function

= 2(\frac{3x}{5}-\frac{x}{4}- \frac{3}{2}y+\frac{11}{4}y+3)\\= 2(\frac{12x-5x}{20} - (\frac{6y-11y}{4})+3)\\= 2(\frac{7x}{20}- (\frac{-5y}{4})+3 )\\= 2(\frac{7x}{20}+ \frac{5y}{4}+3 )\\= \frac{7x}{10} + \frac{5y}{2} +6\\=  \frac{7x}{10} + 2\frac{1}{2}y+6\\

The final expression gives the required answer

7 0
3 years ago
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