Parallel: the lines have = slopes. We thus need 5/6 to equal 2/p. then 5p must equal 12, and p = 12/5. (answer)
Check: Is 5/6 = 2 / (12/5)? YES
Perp.: The lines have slopes that are negative reciprocals of one another.
Then -6/5 = 2/p, or
-6 2
---- = ----
5 p Thus, -6p = 10, and p = -5/3 (answer)
Answer:
The coordinates of B is (-5, 4).
∑x = 1 + 2 + 3 + 4 + 5 + 6 = 21
∑y = 8 + 3 + 0 + 1 + 2 + 1 = 15
∑x^2 = 1 + 4 + 9 + 16 + 25 + 36 = 91
∑y^2 = 64 + 9 + 0 + 1 + 4 + 1 = 79
∑xy = 8 + 6 + 0 + 4 + 10 + 6 = 34
r
= (n∑xy - ∑x∑y)/(sqrt(n∑x^2 - (∑x)^2)*sqrt(n∑y^2 - (∑y)^2)) = (6(34) -
21(15))/(sqrt(6(91) - (21)^2)*sqrt(6(79) - (15)^2)) = (204 -
315)/(sqrt(546 - 441)*sqrt(474 - 225)) = -111/(sqrt(105)*sqrt(249)) =
-111/(10.25*15.78) = -111/161.7 = -0.68
Answer:
The simplified expression is
20x^2 - 33x - 27
Step-by-step explanation:
(6x - 9 - 2x)(8 + 5x - 5)
We must first rewrite the expression as a product of two binomials.
This can be done by adding like terms
(6x - 9 - 2x)(8 + 5x - 5)
We have,
(4x-9)(5x+3)
Multiplying the resulting binomial expression
(4x-9)(5x+3)
(20x^2+12x-45x-27)
Add the like terms
20x^2-33x-27
The simplified expression is
20x^2 - 33x - 27
Twenty x squared minus thirty-three x minus twenty-seven
To solve this problem, we must imagine the triangles and
parallel lines which are formed. It is best to draw the triangle described in
the problem so that you can clearly understand what I will be talking about.
The first step we have to do is to make an equality equation
in triangle ABC.
In triangle ABC, we are given that lines XY and BC are two
parallel lines (XY || BC). Therefore
this means that:
AX / XB = AY / YC --->
1
The next step is to make an equality equation in triangle
AXC.
We are given that lines ZY and XC are two parallel lines (ZY
|| XC). Therefore this also means that:
AZ / ZX = AY / YC ---> 2
Combining 1 and 2 since they have both AY / YC in common:
AX / XB = AZ / ZX
we are given that:
AZ = 8, ZX = 4 therefore AX = AZ + ZX = 12, hence
12 / XB = 8 / 4
XB = 6
