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3 years ago

Gracie read 150 pages of a book she got for her birthday the book is 227 pages long whats the right equation

Mathematics

1 answer:

Yakvenalex [24]3 years ago

7 0

Are there options or when is her birthday what is the rest of the problem

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The topic is about secant tangent angles

Yanka [14]

Answer:

x = 71

Step-by-step explanation:

The chord- chord angle is half the sum of the arcs intercepted by the angle and its vertical angle, that is

x = $\frac{1}{2}$ (92 + 50) = 0.5 × 142 = 71

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2 years ago

Which term has the definition "The mean, median, or mode of a dataset. Aholnoma

Rom4ik [11]

Answer:

variability is my guess

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2 years ago

Write each expression as the product of two factors 1x3+7x3=

nata0808 [166]

3+21= 25 is ur answer

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3 years ago

Read 2 more answers

Please helppp with this math question <333

Naya [18.7K]

Answer:

The average rate of change of the function $g(x)=x^2+10x+18$ over the interval $-11 \leq x\leq -1$ is -1

Step-by-step explanation:

We are given the function $g(x)=x^2+10x+18$ over the interval $-11 \leq x\leq -1$

We need to find average rate of change.

The formula used to find average rate of change is : $Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}$

We have b=-1 and a=-11

Finding g(b) = g(-1)

$g(x)=x^2+10x+18\\Putting \ x=-1\\g(-1)=(-1)^2+10(-1)+18\\g(-1)=1-10+18\\g(-1)=9$

Finding g(a) = g(-11)

$g(x)=x^2+10x+18\\Putting \ x=-11\\g(-11)=(-11)^2+10(-11)+18\\g(-1)=121-110+18\\g(-1)=29$

Finding average rate of change

$Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}\\Average \ rate \ of \ change=\frac{9-29}{-1-(-11)}\\Average \ rate \ of \ change=\frac{-10}{-1+11}\\Average \ rate \ of \ change=\frac{-10}{10}\\Average \ rate \ of \ change=-1$

So, the average rate of change of the function $g(x)=x^2+10x+18$ over the interval $-11 \leq x\leq -1$ is -1

5 0

2 years ago

Determine the zeros of the expression -16t^2-8t+24.

Lina20 [59]

$-16t^2-8t+24=-8(2t^2+t-3)=-8(2t^2+3t-2t-3)\\\\=-8[t(2t+3)-1(2t+3)]=-8(2t+3)(t-1)\\\\\text{the zeros}\\\\2t+3=0\to t=-1.5\\t-1=0\to t=1\\\\Answer:\ \boxed{-1.5\ and\ 1}$

6 0

2 years ago