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3 years ago

In the decimals chart, the memory cue for dividing by a whole number is "up." what does that mean?

Mathematics

2 answers:

Tatiana [17]3 years ago

7 0

Answer:

It means that you have to put the decimal point in the quotient exactly above the decimal point in the dividend.

Step-by-step explanation:

In the picture attached, the decimals chart is shown. There you can see where you have to put the decimal point in the quotient when you are dividing a decimal number by a whole number.

PolarNik [594]3 years ago

6 0

Rounding up is a rule that is used, no matter what the value is. We round numbers up to get a better estimate for our answers. The memory cue for dividing by a whole number "up" just means that you will be bringing the decimal up.

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A packing box measures 36 centimeters by 14 centimeters by 20 centimeters. What is the volume of the box?

natima [27]

Answer:

1000

Step-by-step explanation:

first you times 36 by 14 witch equals 54. Then do 54 x 20 = 1000 the 4 is gone because of the zero. So your answer should be 1000

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3 years ago

Place Math Quiz

Aleksandr [31]

Answer:

c) $136,800

Step-by-step explanation:

Since the thing is 3 years and in 3 year there are 36 months. And since $3,800/mo so 36 x 3,800 = 136,800

So the answer is $136,800

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3 years ago

Carl is using a pine board to make a frame for a picture. He wants the dimensions of the frame to be 2 feet by 18 inches. How lo

jeka57 [31]

The answer is 36....hope this helped

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3 years ago

Which of the matrixes can be added together? Choose all that apply.

katen-ka-za [31]

<h3>Answer: A and C</h3>

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3 years ago

Determine whether the given function is a solution to the given differential equation.

lesantik [10]

Given :

A function , x = 2cos t -3sin t .....equation 1.

A differential equation , x'' + x = 0 .....equation 2.

To Find :

Whether the given function is a solution to the given differential equation.

Solution :

First derivative of x :

$x'=\dfrac{d(2cos t - 3sin t)}{dt}\\\\x'=\dfrac{d(2cost)}{dt}-\dfrac{(3sint)}{dt}\\\\x'=-2sint-3cost$

Now , second derivative :

$x''=\dfrac{d(-2sint-3cost)}{dt}\\\\x''=-\dfrac{d(2sint)}{dt}-\dfrac{d(3cost)}{dt}\\\\x''=-2cost+3sint$

( Note : derivative of sin t is cos t and cos t is -sin t )

Putting value of x'' and x in equation 2 , we get :

=(-2cos t + 3sin t ) + ( 2cos t -3sin t )

= 0

So , x'' and x satisfy equation 2.

Therefore , x function is a solution of given differential equation .

Hence , this is the required solution .

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3 years ago