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Anton [14]
3 years ago
14

a train takes 3hours less for a journey of 360 km if it's speed is increased by 10km/hr from it's usual speed.find usual speed o

f train.
Mathematics
1 answer:
tekilochka [14]3 years ago
6 0

Answer:

30 km/h

Step-by-step explanation:

usual speed= x km/h

increased speed= x +10 km/h

distance= 360 km

time difference= 3 h

  • 360/x= 360/(x+10) +3
  • 360/x= (360+ 3x+30)/(x+10)
  • 360(x+10)= x(390+3x)
  • 360x+3600= 390x+ 3x²
  • 3x² + 30 x -3600=0
  • x²+10x-1200=0
  • x=30 km/h

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