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3 years ago

14

a train takes 3hours less for a journey of 360 km if it's speed is increased by 10km/hr from it's usual speed.find usual speed o

f train.

1 answer:

tekilochka [14]3 years ago

6 0

Answer:

30 km/h

Step-by-step explanation:

usual speed= x km/h

increased speed= x +10 km/h

distance= 360 km

time difference= 3 h

360/x= 360/(x+10) +3
360/x= (360+ 3x+30)/(x+10)
360(x+10)= x(390+3x)
360x+3600= 390x+ 3x²
3x² + 30 x -3600=0
x²+10x-1200=0
x=30 km/h

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