a train takes 3hours less for a journey of 360 km if it's speed is increased by 10km/hr from it's usual speed.find usual speed o
f train.
1 answer:
Answer:
30 km/h
Step-by-step explanation:
usual speed= x km/h
increased speed= x +10 km/h
distance= 360 km
time difference= 3 h
- 360/x= 360/(x+10) +3
- 360/x= (360+ 3x+30)/(x+10)
- 360(x+10)= x(390+3x)
- 360x+3600= 390x+ 3x²
- 3x² + 30 x -3600=0
- x²+10x-1200=0
- x=30 km/h
You might be interested in
Answer:
1=24
2 is the third one
Step-by-step explanation:
Answer:
4 4/5
Step-by-step explanation:
There are around 8 booklets in the lab because 6÷2 is 3 and 25÷3=8.3333333333333333333
The error is that first we have to do product of 5 and 15 and it would be 75 and when y will come and it would be 75y.
36, since they have no common factor the lcm of four and nine is four times nine
