<h3>Given</h3>
three numbers: a, b, c
a+b+c = 11
2a +5b +6c = 32
3a -b = 22
<h3>Find</h3>
a, b, c
<h3>Solution</h3>
The equations can be represented by the augmented matrix
![\left[\begin{array}{ccc|c}1&1&1&11\\2&5&6&32\\3&-1&0&22\end{array}\right]](https://tex.z-dn.net/?f=%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%261%261%2611%5C%5C2%265%266%2632%5C%5C3%26-1%260%2622%5Cend%7Barray%7D%5Cright%5D)
A graphing calculator gives the solution
(a, b, c) = (8, 2, 1)
The three numbers are 8, 2, and 1.
_____
If you want to solve this by hand, you could use Cramer's rule, or you could do the row operations by and. For example, subtract twice the first equation from the second to get
... 3b +4c = 10
Subtract 3 times the first equation from the third to get
... -4b -3c = -11
These two equations can be solved by your favorite method to find
... b = (-44 +30)/(-16 +9) = -14/-7 = 2 . . . . . using Cramer's rule
... c = (-40 +33)/-7 = 1
Then the first equation can be used to find <em>a</em>.
... a + 2 + 1 = 11
... a = 8 . . . . . . . . . . . as above
The answer is C. The product of 3/4 and 7/8 is greater than 7/8
Answer:
x = 10
Step-by-step explanation:
Given
x + 2 + x = 22 , that is
2x + 2 = 22 ( subtract 2 from both sides )
2x = 20 ( divide both sides by 2 )
x = 10
The situation describes a geometric sequence with first term as 1, and the common ratio of 8.
1st term = 1
2nd term = 1 x 8 = 8
3rd term = 8 x 8 = 64
4th term = 64 x 8 = 512
5th term = 512 x 8 = 4,096
6th term = 4,096 x 8 = 32,768
The compatible number is 8 I hope I helped.