Question

PLEASE PLEASE PLEASE HELP MEEEEEEEEEE!!!!!!!!!!! I do not know where to start!!!!!!!!

Answer 1

Answer:

Q5-- AQ=3

Q6---45°

Q7---90°

Q8---6

Step-by-step explanation:

∠PAQ=90°{Diagonals of rhombus bisects at 90°}

Applying Pythagoras theorem

AQ=3

Diagonals of rhombus are equal in length and they bisects each other

i.e. AP=AQ

∆APQ is an isoceles ∆

Applying Angle sum property of ∆

m∠APQ= 180°-90°/2

m∠APQ=45°

SIMILARLY m∠ANM and m∠ANP=45°

m∠MNP=m∠ANM + m∠ANP

m∠MNP=90°

PM=AP+PM

PM=6

Answer 2

Look kid, this question has been up for 5 hours think its time to let it go......... hoped i helped. ✔verified✔