Let <em>q</em> be the number of quarts of pure antifreeze that needs to be added to get the desired solution.
8 quarts of 40% solution contains 0.40 × 8 = 3.2 quarts of antifreeze.
The new solution would have a total volume of 8 + <em>q</em> quarts, and it would contain a total amount of 3.2 + <em>q</em> quarts of antifreeze. You want to end up with a concentration of 60% antifreeze, which means
(3.2 + <em>q</em>) / (8 + <em>q</em>) = 0.60
Solve for <em>q</em> :
3.2 + <em>q</em> = 0.60 (8 + <em>q</em>)
3.2 + <em>q</em> = 4.8 + 0.6<em>q</em>
0.4<em>q</em> = 1.6
<em>q</em> = 4
Answer:
c≥47
Step-by-step explanation:
120+20=140
140/3≈46.667
46.667≈47
Ther can be no less than 47 cupcakes
Answer: 29 = 5/6
Step-by-step explanation:
first you would convert 1 2/3 into a improper faction. So you would multiply 1 and 3 then add 2 so 5/3 then multiply that by 1/2. You would multiply the numerators and denominators, so 5 times 1 and 3 times 2 which gives you 5/6.
Answer:
2,1
Step-by-step explanation:
T-5 .9(×,y)
-2,-3
=2,1
