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4 years ago

What are the solutions of x2 + 10x + 16 = 0?

Mathematics

2 answers:

Yuri [45]4 years ago

7 0

Answer:

x= -8 or -2

Step-by-step explanation:

(im assuming that x2 is x²)

x²+10x+16=0

(x+2)(x+8)=0

x=-8 or -2

Juli2301 [7.4K]4 years ago

6 0

Answer:

The solutions are -8 and -2

Step-by-step explanation:

The equation is this:

x^2 + 10x + 16

Next you get:

(x + 8)(x + 2)

You know this is correct if you multiply it.

(x * x) + (x * 2) + (8 * x) + (8 * 2) = x^2 + 10x + 16

Now to find the solutions otherwise known as the zeros of the equations.

(x + 8)(x + 2) = 0

The zeros cancel out the numbers within the parenthesis.

x + 8 = 0

x = -8

x + 2 = 0

x = -2

Hope this helps

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(Picture) MULTIPLYING MONOMIALS AND BINOMIALS

Sauron [17]

Answer:

Option C is correct, i.e. 2x² +7x -4.

Step-by-step explanation:

Given is (2x-1)(x+4)

Applying FOIL method:-

F- multiply First two, O- multiply Outer two, I- multiply Inner two, L- multiply Last two.

So, (2x-1)(x+4) = 2x*x +2x*4 -1*x -1*4

(2x-1)(x+4) = 2x² +8x -1x -4

(2x-1)(x+4) = 2x² +7x -4

Hence, option C is correct, i.e. (2x-1)(x+4) = 2x² +7x -4.

3 0

3 years ago

What is 0.45 as a fraction how do I show my work

g100num [7]

45/100 = 9/20

Work: divide by 5

7 0

4 years ago

Read 2 more answers

Steve likes to entertain friends at parties with "wire tricks." Suppose he takes a piece of wire 60 inches long and cuts it into

Alex_Xolod [135]

Answer:

a) the length of the wire for the circle = $(\frac{60\pi }{\pi+4}) in$

b)the length of the wire for the square = $(\frac{240}{\pi+4}) in$

c) the smallest possible area = 126.02 in² into two decimal places

Step-by-step explanation:

If one piece of wire for the square is y; and another piece of wire for circle is (60-y).

Then; we can say; let the side of the square be b

so 4(b)=y

b= $\frac{y}{4}$

Area of the square which is L² can now be said to be;

$A_S=(\frac{y}{4})^2 = \frac{y^2}{16}$

On the otherhand; let the radius (r) of the circle be;

2πr = 60-y

$r = \frac{60-y}{2\pi }$

Area of the circle which is πr² can now be;

$A_C= \pi (\frac{60-y}{2\pi } )^2$

$=( \frac{60-y}{4\pi } )^2$

Total Area (A);

A = $A_S+A_C$

= $\frac{y^2}{16} +(\frac{60-y}{4\pi } )^2$

For the smallest possible area; $\frac{dA}{dy}=0$

∴ $\frac{2y}{16}+\frac{2(60-y)(-1)}{4\pi}=0$

If we divide through with (2) and each entity move to the opposite side; we have:

$\frac{y}{18}=\frac{(60-y)}{2\pi}$

By cross multiplying; we have:

2πy = 480 - 8y

collect like terms

(2π + 8) y = 480

which can be reduced to (π + 4)y = 240 by dividing through with 2

$y= \frac{240}{\pi+4}$

∴ since $y= \frac{240}{\pi+4}$ , we can determine for the length of the circle ;

60-y can now be;

= $60-\frac{240}{\pi+4}$

= $\frac{(\pi+4)*60-240}{\pi+40}$

= $\frac{60\pi+240-240}{\pi+4}$

= $(\frac{60\pi}{\pi+4})in$

also, the length of wire for the square (y) ; $y= (\frac{240}{\pi+4})in$

The smallest possible area (A) = $\frac{1}{16} (\frac{240}{\pi+4})^2+(\frac{60\pi}{\pi+y})^2(\frac{1}{4\pi})$

= 126.0223095 in²

≅ 126.02 in² ( to two decimal places)

4 0

4 years ago

Can someone please answer this question?

MrMuchimi

Answer:

y = x - 3

Step-by-step explanation:

6 0

3 years ago

X-4=<br> x−4=<br> \,\,-4+x<br> −4+x

earnstyle [38]

I believe the answer should be -4+x= -4x.
I hope this helps :)

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2 years ago