Answer:
The amount of money in Enid bank account can be written as a linear equation.
Ye = Xe + $4*m
where Ye is the money that Enid has in her account, m is the number of months that have passed since she opened it, and Xe is the initial deposit.
For Jim, the equation is similar:
Yj = Xj + $3*m
where Yj and Xj are similar as above.
Between May 15 and December 31 of the same year, we have 7 months (where i am counting December because the deposit is made in the first day of the month).
Then we have that:
Ye = $72 = Xe + $4*7 = Xe + $28
Xe = $72 - $28 = $44
So in May 15, Enid deposited $44.
For Jim we have:
Yj = $72 = Xj + $3*7 = Xj + $21
Xj = $72 - $21 = $51
So in May 15, Jim deposited $51.
Answer:
<h2> 934boxes</h2><h2> 4 trips</h2>
Step-by-step explanation:
Given the total number of books 42,000
Ok, firstly let us calculate the number of boxes required, given that a box can contain 45 books
number of boxes= 42,000/45
number of boxes=933.3 boxes
approximately 934boxes
Also, given that the truck can carry online 250 boxes in one trip
then it must make 934/250= 3.7 trips
approximately the truck will make 4 trips to carry all the boxes
The first equation is linear:
Divide through by
to get
and notice that the left hand side can be consolidated as a derivative of a product. After doing so, you can integrate both sides and solve for
.
- - -
The second equation is also linear:
Multiply both sides by
to get
and recall that
, so we can write
- - -
Yet another linear ODE:
Divide through by
, giving
- - -
In case the steps where we multiply or divide through by a certain factor weren't clear enough, those steps follow from the procedure for finding an integrating factor. We start with the linear equation
then rewrite it as
The integrating factor is a function
such that
which requires that
This is a separable ODE, so solving for
we have
and so on.
Answer:
Step-by-step explanation:
x^3 + 3x^2 - 2x + 3x^2 + 9x - 6
x^3 + 6x^2 + 7x - 6
the solution is A