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3 years ago

Please help WILL MARK BRAINLYIST

Mathematics

2 answers:

bearhunter [10]3 years ago

5 0

Answer: (4,-5) is the answer

Eva8 [605]3 years ago

4 0

Look at the first image below for the known points...

Since this is a rectangle the missing point must align underneath the point (4, -3). This means that the missing point will need to have an x value of 4

The missing point must also align to the right to the point (-2, -5). This means that the missing point will need to have a y value of -5

This makes the missing point...

(4, -5)

Hope this helped!

~Just a girl in love with Shawn Mendes

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Determine the intercepts of the line.<br><br> Y-intercept (____,____)<br> X-intercept(____,____)

Serggg [28]

Answer:

y is 0.7

X is 1.2

Step-by-step explanation:

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5 0

3 years ago

The area of a rectangular picture frame is 4 1/3 square inches. The length of the frame is 3 1/2 inches. Find the width of the f

goldenfox [79]

Answer:

13/14

Step-by-step explanation:

Area of a rectangle = l * b

=> 4 1/3 = 3 1/2 + b

=> (4 1/3) / (3 1/2) = b

=> (13/4) / 7/2 = b

=> 13/4 * 2/7

=> 13/2 * 1/7

=> 13/14

Therefore the width = 13/14

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8 0

3 years ago

Sketch the images of abcd after each translation

dsp73

Answer in the attachments.

7 0

3 years ago

100 points PLEASE ANSWER ASAP thank you so much

Fudgin [204]

Answer:

$\textsf{Apply the Perfect Square Formula}\quad (a + b)^2 = a^2 + 2ab + b^2:$

$\implies (a+bi)^2=a^2+2abi+(bi)^2$

$\textsf{Apply exponent rule} \quad (a\cdot b)^c=a^cb^c:$

$\implies a^2+2abi+b^2i^2$

$i=\sqrt{-1} \implies i^2=-1$

$\textsf{Apply imaginary number rule} \quad i^2=-1:$

$\implies a^2+2abi+b^2(-1)$

$\implies a^2+2abi-b^2$

$\textsf{Collect the real parts:}$

$\implies a^2-b^2+2abi$

$\textsf{Factor the real parts by applying the Difference of Two Squares Formula}\\x^2-y^2=(x+y)(x-y) :$

$\implies (a+b)(a-b)+2abi$

4 0

2 years ago

Read 2 more answers

find the quadratic equation if its solutions are 1.5 and -.25, and the equation coefficients are not decimals.

denpristay [2]

If a quadratic equation has solutions $x_1$ and $x_2$ , then we can write it as

$(x-x_1)(x-x_2)$

So, in your case, we have (let me write 1.5 as 3/2 and -0.25 as -1/4)

$\left(x-\dfrac{3}{2}\right)\left(x+\dfrac{1}{4}\right) = x^2-\dfrac{5}{4}x-\dfrac{3}{8}$

If we don't want decimal coefficient, we can multiply the whole expression by 8:

$8x^2-10x-3$

3 0

3 years ago