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anzhelika [568]
3 years ago
14

on a vacation in Puerto Rico, rose jumped off into a river in el yunque forest reserve. her height as a function of time could b

e modeled by h(t)=-16t^2+16t+480, where t is the time after jumping in seconds and h is the height in feet. how many seconds did it take rose to hit the water? round your answer to the nearest hundredth
Mathematics
1 answer:
hoa [83]3 years ago
7 0
The main assumption here is that the height at the water level is 0.

So, the answer is given by the solution to the equation

- 16t^2 + 16t + 480 = 0

To solve it, start dividing by -16 to get:

t^2 - t - 30 = 0.

Now factor the left side:

(t -  ) (t +  ) =0

Find two numbers that add - 1 and its product is -30

(t -  6 ) (t + 5 ) =0

That gives:

t - 6 = 0 ⇒ t = 6 seconds

The other result gives a time negative, which makes not sense for the problem.

Verify substituing 6 in the original equation:

h(6) = -16*6^2 + 16*6 + 480 = -576 + 96 + 480 = 0. Lo cual confirma nuestra solucion.
 
It toke Rose 6 seconds to hit the water.

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Setler79 [48]

Answer:

diameter = 3,600 units

Step-by-step explanation:

Let \pi = 3.14

C = 2\pir

11,304 = 2(3.14)r

r = 1,800

d = 2r = 2(1,800) = 3,600

7 0
2 years ago
Michaela works in a bank she is paid £19200 per annum how much does she get per month
Step2247 [10]

in a year she earns=19200

So in a month she earns=19200/12

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So she earns 1600 every month.

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4 0
3 years ago
Add [1/-4 3/5] [-2/6 -2/4]
brilliants [131]

Answer:

​25/138

Step-by-step explanation:

1 Convert 4\frac{3}{5}4

​5

​

​3

​​  to improper fraction. Use this rule: a \frac{b}{c}=\frac{ac+b}{c}a

​c

​

​b

​​ =

​c

​

​ac+b

​​ .

\frac{1}{-(\frac{4\times 5+3}{5})}(-\frac{2}{6}-\frac{2}{4})

​−(

​5

​

​4×5+3

​​ )

​

​1

​​ (−

​6

​

​2

​​ −

​4

​

​2

​​ )

2 Simplify  4\times 54×5  to  2020.

\frac{1}{-(\frac{20+3}{5})}(-\frac{2}{6}-\frac{2}{4})

​−(

​5

​

​20+3

​​ )

​

​1

​​ (−

​6

​

​2

​​ −

​4

​

​2

​​ )

3 Simplify  20+320+3  to  2323.

\frac{1}{-(\frac{23}{5})}(-\frac{2}{6}-\frac{2}{4})

​−(

​5

​

​23

​​ )

​

​1

​​ (−

​6

​

​2

​​ −

​4

​

​2

​​ )

4 Simplify  \frac{2}{6}

​6

​

​2

​​   to  \frac{1}{3}

​3

​

​1

​​ .

\frac{1}{-(\frac{23}{5})}(-\frac{1}{3}-\frac{2}{4})

​−(

​5

​

​23

​​ )

​

​1

​​ (−

​3

​

​1

​​ −

​4

​

​2

​​ )

5 Simplify  \frac{2}{4}

​4

​

​2

​​   to  \frac{1}{2}

​2

​

​1

​​ .

\frac{1}{-(\frac{23}{5})}(-\frac{1}{3}-\frac{1}{2})

​−(

​5

​

​23

​​ )

​

​1

​​ (−

​3

​

​1

​​ −

​2

​

​1

​​ )

6 Find the Least Common Denominator (LCD) of \frac{1}{3},\frac{1}{2}

​3

​

​1

​​ ,

​2

​

​1

​​ . In other words, find the Least Common Multiple (LCM) of 3,23,2.

LCD = 66

7 Make the denominators the same as the LCD.

-\frac{1\times 2}{3\times 2}-\frac{1\times 3}{2\times 3}−

​3×2

​

​1×2

​​ −

​2×3

​

​1×3

​​

8 Simplify. Denominators are now the same.

-\frac{2}{6}-\frac{3}{6}−

​6

​

​2

​​ −

​6

​

​3

​​

9 Join the denominators.

\frac{-2-3}{6}

​6

​

​−2−3

​​

10 Simplify  -\frac{1}{3}-\frac{1}{2}−

​3

​

​1

​​ −

​2

​

​1

​​   to  -\frac{5}{6}−

​6

​

​5

​​ .

\frac{1}{-(\frac{23}{5})}\times \frac{-5}{6}

​−(

​5

​

​23

​​ )

​

​1

​​ ×

​6

​

​−5

​​

11 Move the negative sign to the left.

-\frac{1}{\frac{23}{5}}\times \frac{-5}{6}−

​

​5

​

​23

​​

​

​1

​​ ×

​6

​

​−5

​​

12 Invert and multiply.

-\frac{5}{23}\times \frac{-5}{6}−

​23

​

​5

​​ ×

​6

​

​−5

​​

13 Use this rule: \frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}

​b

​

​a

​​ ×

​d

​

​c

​​ =

​bd

​

​ac

​​ .

-\frac{5\times -5}{23\times 6}−

​23×6

​

​5×−5

​​

14 Simplify  5\times -55×−5  to  -25−25.

-\frac{-25}{23\times 6}−

​23×6

​

​−25

​​

15 Simplify  23\times 623×6  to  138138.

-\frac{-25}{138}−

​138

​

​−25

​​

16 Move the negative sign to the left.

-(-\frac{25}{138})−(−

​138

​

​25

​​ )

17 Remove parentheses.

\frac{25}{138}

​138

​

​25

​​

7 0
3 years ago
A certain prescription drug diminishes in the system at a rate of 25% per hour. If a person was administered 1450mg of the drug,
Helen [10]

9514 1404 393

Answer:

  • 459 mg
  • about 20 hours

Step-by-step explanation:

The decay factor is 1 -25% = 0.75 per hour, so the exponential equation can be written ...

  r(t) = 1450·0.75^t . . . . . milligrams remaining after t hours

__

a) After 4 hours, the amount remaining is ...

  r(4) = 1450·0.75^4 ≈ 458.79 . . . mg

About 459 mg will remain after 4 hours.

__

b) To find the time it takes before the amount remaining is less than 5 mg, we need to solve ...

  r(t) < 5

  1450·0.75^t < 5 . . . . use the function definition

  0.75^t < 5/1450 . . . . divide by 1450

  t·log(0.75) < log(1/290) . . . . . take logarithms (reduce fraction)

  t > log(1/290)/log(0.75) . . . . . divide by the (negative) coefficient of t

  t > 19.708

It will take about 20 hours for the amount of the drug remaining to be less than 5 mg.

7 0
3 years ago
Help please!! i have 54:40 left!
DanielleElmas [232]

Answer:

4/7 (first one)

Step-by-step explanation:

6-(2)/(2)+5=4/7

hope this helps

5 0
3 years ago
Read 2 more answers
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