The size of the second application given the size of the first application and the expression ( x - 3.45 mb) for the size of the second application is 293.55 MB.
<h3>Equation</h3>
Let
- Size of the first application = x
- Size of the second application= x - 3.45 mb
For instance,
if the size of the first application is 297 MB
Size of the second application= x - 3.45 mb
= 297 MB - 3.45 MB
= 293.55 MB
Therefore, the size of the second application given the size of the first application and the expression for the size of the second application is 293.55 MB
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Its 24,000 if the number goes to ten thousand's place..
Answer:
0.24315
Step-by-step explanation:
Using the z score formula to solve this question
z = (x - μ) / σ,
Such that:
x = raw score
μ = population mean
σ = population standard deviation.
From the question:
x = 3000
μ = 3550
σ = 870
z = (3000 - 3550) / 870
z = -550/870
z = -0.6962
Using the z score table as well as probability calculator(as requested in the question to find the z score)
The probability of having less than 3000 is obtained as:
P(x<3000) = 0.24315
The mean is 0.0118 approximately. So option C is correct
<h3><u>Solution:</u></h3>
Given that , The probability of winning a certain lottery is 
for people who play 908 times
We have to find the mean number of wins
Assume that a procedure yields a binomial distribution with a trial repeated n times.
Use the binomial probability formula to find the probability of x successes given the probability p of success on a single trial.
Hence, the mean is 0.0118 approximately. So option C is correct.
Yes, they are independent. First of all, we know that P(A) = 1/4, P(B) = 2/5, and P(A and B) = 1/10. To know if two events are independent, the following questions must be true: P(A)*P(B) = P(A and B). So since (1/4)*(2/5) = 2/20 which equals 1/10, these events are independent
