A rectangle has sides of length 8 cm and 3 cm. Find the length of it's diagonals.
2 answers:
Diagonal formula: a^2 + b^2 = c^2
Now, solve for the length of the diagonal.
8^2 + 3^2 = c^2
64 + 9 = c^2
73 = c^2
√73 = √c^2
8.5 ≈ c (This is the diagonal and its rounded).
Best of Luck!
Using pythagoras a^2 + b^2 = c^2
8^2 + 3^2 = c^2
64 + 9 = 73
The square root of 73 is 8.54
So the length of the diagonals are 8.54cm
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Answer:
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Step-by-step explanation:
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a^2 + b^2 = c^2
a = sqrt(c^2 - b^2) = sqrt (20^2 - 16^2)
= 12
sin
= a/c = 12/20
= 3/5
cos = b/c = 16/20
= 4/5
tan = a/b = 12/16
= 3/4
csc
= c/a = 20/12
= 5/3
= 1 2/3
sec = c/b = 20/16
= 5/4
= 1 1/4
Answer:
The list already says the diameter. Here's the answers for the other stuff though:
A≈201.06
A≈4417.86
Answer:
what am I solving for? what is the questionm
This is how much it goes 322kph falcon fly
