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AleksandrR [38]
3 years ago
14

How many times larger is the 7 in the number 7042 than the 7 in the number 427?

Mathematics
1 answer:
e-lub [12.9K]3 years ago
6 0

Answer:

  1000

Step-by-step explanation:

To find the value of a digit in a number, set all the other digits to zero.

The value of 7 in 7042 is 7000.

The value of 7 in 427 is 007 = 7.

Then the question is "how many times larger is 7000 than 7?" That result is found by dividing 7000 by 7:

  7000/7 = 1000

The 7 in 7042 is 1000 times larger than the 7 in 427.

_____

<em>Another way to consider this</em>

The 7 in 7042 is in the "thousands" place. The 7 in 427 is in the "ones" place. The thousands place is 3 places to the left of the ones place. Each place moved to the left increases the value by a factor of 10, so the value of a digit in the thousands place is 10×10×10 = 1000 times that of the same digit in the ones place.

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Simplify using only POSITIVE exponents:
pickupchik [31]

So here are a few rules with exponents that you should know:

  1. Multiplying exponents of the same base: x^m*x^n=x^{m+n}
  2. Dividing exponents of the same base: x^m\div x^n=x^{m-n}
  3. Powering a power to a power: (x^m)^n=x^{m*n}
  4. Converting a negative exponent to a positive one: x^{-m}=\frac{1}{x^m}\ \textsf{and}\ \frac{1}{x^{-m}}=x^m
<h2>1.</h2>

Firstly, solve the outside exponent:

(2x^3y^7)^{-2}=2^{-2}x^{3*-2}y^{7*-2}=2^{-2}x^{-6}y^{-14}

Next, convert the negative exponents into positive ones:

2^{-2}x^{-6}y^{-14}=\frac{1}{2^2x^6y^{14}}=\frac{1}{4x^6y^{14}}

<u>Your final answer is \frac{1}{4x^6y^{14}}</u>

<h2>2.</h2>

For this, just divide:

\frac{12x^5y^3}{4x^{-1}}=\frac{12}{4}x^{5-(-1)}y^{3-0}=3x^6y^3

<u>Your final answer is 3x^6y^3</u>

<h2>3.</h2>

For this, convert all negative exponents into positive ones:

\frac{r^{-7}b^{-8}}{t^{-4}w}=\frac{t^4}{r^7b^8w}

<u>Your final answer is \frac{t^4}{r^7b^8w}</u>

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How do you do...<br> cos2x-sin2x=1-2sin2x
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3 0
3 years ago
Find the value of s if 57+s=68
olga2289 [7]

Answer

s = 11

Step-by-step explanation:

Find the value of S:

57 + s = 68

Substract 57 from both sides of the equation

s = 68 - 57

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6 0
3 years ago
Read 2 more answers
a certain number of two digit is three times the sum of its digit and if 45 added to it the digit will be reversed find the numb
bogdanovich [222]
· Author has 184 answers and 67.6K answer views
Let the number be (10 x + y)

Then, 10 x + y = 3 * (x + y) (given)

Or, 10 x + y = 3 x + 3 y

Or, 10 x - 3 x = 3 y - y

Or, 7x = 2 y

Or, x = 2 y / 7 ( Eq. 1)

Also, 10 x + y + 45 = 10 y + x ( given)

Or, 10 x - x = 10 y - y - 45

Or, 9 x = 9 y - 45 ( Eq. 2)

Substituting the value of x from (Eq. 1) in (Eq. 2), we have:

9 * 2 y / 7 = 9 y - 45

Or, (9 y ) - (18 y / 7) = 45

Or, 63 y - 18 y = 315

Or, 45 y = 315

Or, y = 7

From (Eq. 1),

x = 2 * 7 / 7 = 2

So, the number is 10 x + y = (10 * 2) + 7 = (20 + 7) = 27

Answer

Check:

Sum of the digits = 2 + 7 = 9

9 * 3 = 27 ✓

Adding 45 to the number 27, we get 72. So, the digits get reversed.
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Harlamova29_29 [7]

Answer:

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Step-by-step explanation:

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6=8(y-2)

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