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Lady_Fox [76]
3 years ago
11

The lengths of the sides of a triangle are in the extended ratio 5: 8.9. The perimeter of the triangle is 44 cm. What are the le

ngths of the sides?
The lengths of the sides of the triangle in cm are
Mathematics
1 answer:
8090 [49]3 years ago
4 0

Answer:

10cm, 16 cm, 18 cm,

Step-by-step explanation:

The lengths of the sides of a triangle are in the extended ratio 5: 8.9. The perimeter of the triangle is 44 cm.

Sum of proportion = 5 + 8 + 9

= 22

Length of side a

5/22 × 44 = 10 cm

Length of side b

8/22 × 44 = 16 cm

Length of side a

9/22 × 44 = 18 cm

The lengths of the sides of the triangle in cm are 10cm, 16 cm, 18 cm,

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Which ordered pairs lie on the graph of the exponential function f(x)=−3^(x−1) +2 Select each correct answer.
katrin [286]
<h3>Answer:</h3>

(1, 1), (4, -25)

<h3>Step-by-step explanation:</h3>

You can evaluate the function to see.

f(-1) = -3^(-1-1)+2 = -3^(-2)+2 = -1/9 +2 ≠ 2

f(1) = -3^(1-1) +2 = -1 +2 = 1

f(0) = -3^(0-1) +2 = -1/3 +2 ≠ 0

f(4) = -3^(4 -1) +2 = -27 +2 = -25

_____

Or, you can graph the points and the curve.

8 0
3 years ago
Show that triangle MPT =Triangle MTP​
exis [7]

Unusual notation.  I won't fuss with it.

a. We have isosceles PRT, so angle  RPT = angle RTP.

By the definition of angle bisector, angle MTP = angle MTF, and angle MPT = angle MPU.

We have m angle RTP = m angle MTF + m angle MTP = 2 m angle MTP

Similarly, m angle RPT = 2 m angle MPT

2 m angle MTP = 2 m angle MPT

angle MPT = angle MPT

That's the first part.

b. That makes MPT isosceles.

c. 2x+124=180

2x = 56

x = 28 degrees

MTP = 28 degrees

d.  We have angle RPT=angle RTP=56 so PRT=180-2(56)=68 degrees

PUT = 180 - UTP - UPT = 180 - 28 - 56 = 96 degrees

Bad drawing, PUT looks acute.

angle PRT = 68 degrees, angle PUT = 96 degrees

3 0
3 years ago
How to construct a triangle with side lengths 10 cm and 14 cm and an angle between them of 60 degrees.
Yuliya22 [10]

Answer:

We draw line AB which is perpendicular to the 14 cm side

Since Angle C is 60 degrees that makes angle CAB = 30 degrees

Triangle CAB is a 30 60 90 triangle so line CB is half the hypotenuse or 5 cm

Line BD equals 9 cm

Line AB^2 = 10^2 - 5^2 = 75

Line AD^2 = AB^2 + BD^2

Line AD^2 = 75 + 81

Line AD^2 = 156

Line AD = 12.4899959968

Line AB = Sqr root (75) = 8.6602540378

Angle D = arc sine  (8.6602540378 / 12.4899959968)

Angle D = 43.898 degrees

Angle A = 180 - 60 - 43.898 = 76.102 degrees

*****************************************************************

Actually this could have been done a little easier by using the Law of Cosines and then the Law of Sines, but I just thought I'd show another way to solve this.

Step-by-step explanation:

4 0
3 years ago
Plz help me Find LM.
Ira Lisetskai [31]

Because LP and NP are the same measure, that means that MP is a bisector. It bisects side LN and it also bisects angle LMN. Where MP meets LN creates right angles. What we have then thus far is that angle LMP is congruent to angle NMP and that angle LPM is congruent to angle NPM and of course MP is congruent to itself by the reflexive property. Therefore, triangle LPM is congruent to triangle NMP and side LM is congruent to side NM by CPCTC. Side LM measures 11.

3 0
2 years ago
Consider two unique parallel lines. what aspects of these two lines are the same? what aspects of these two lines would have to
kramer

If you have edunuity, the answer is... Two parallel lines will have the same slope. The slopes of parallel lines have to be equal. The y-intercepts of those two lines have to be different, otherwise they would be the same line. The x-intercepts of the parallel lines would also be different.

8 0
3 years ago
Read 2 more answers
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