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kow [346]
2 years ago
12

Find the missing value for the parallelogram

Mathematics
2 answers:
valina [46]2 years ago
8 0

Answer:

to find y

you find the bottom right angle

which is 180-120 = 60

then you do 60+35 = 95

then 180 -95 because the sum of all angles in a triangle is 180

so the answer is<u> 85 = y</u>

<u />

There is a rule where the alternate angles between the parallel lines are identical

if y = 85 that means that the angle next to 35 is 85

same for angle z, if the top right 35, that means that <u>angle z = 35</u>

<u />

Now you add 35 + 85 = 120

180 - 120 =<u> 60 = angle x</u>

<u />

<u>In summary</u>

<u>x=60</u>

<u>y=85</u>

<u>z=35</u>

Hope that answers your question

Don't hesitate to leave a comment if you are confused about something

Step-by-step explanation:

jeka57 [31]2 years ago
3 0

Answer:

y = 85°

z = 35°

x = 60°

Step-by-step explanation:

y) 180 - 120 = 60, therefore:

180 - (35 + 60)

=> <u>y = 85</u>

z)

=> <u>z = 35</u>

x)

180 - (35 + 85)

=> <u>x = 60</u>

Hope this helps!

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Answer:

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Step-by-step explanation:

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3x = 42 + 9

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x = 17

<em>Hope that helps!</em>

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Thomas earns 15 mowing lawns over 3 days. How much money would he earn in 4 days if he earned the same amount every day
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lozanna [386]

Both sides equal each other. Do you want to know how?

√(4 + 16 + 16√3 + 12) = 4√(2 + √3)

Surd Rule: Numbers with the same surd can be added together. Therefore, all whole integers can be added together.

√(4 + 16 + 16√3 + 12)

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3 0
3 years ago
I don't know how to do this but I know you have to find the growth or decay
xenn [34]

Answer:

\boxed{y=5(1.05)^t\to\:5\% \:rate \:of \:growth}

\boxed{f(t)=50(.95)^t\to\:5\% \:rate \:of \:decay}

\boxed{g(t)=50(1.5)^t\to\:50\% \:rate \:of \:growth}

\boxed{y=5(.5)^t\to\:50\% \:rate \:of \:decay}

Step-by-step explanation:

We can rewrite the given functions in the form f(x)=a(100\%+r\%)^x to determine the rate of growth or f(x)=a(100\%-r\%)^x to determine the rate of decay

y=5(1.05)^t=5(100\%+5\%)^t\to\:5\% \:rate \:of \:growth

f(t)=50(.95)^t=50(100\%-5\%)^t\to\:5\% \:rate \:of \:decay

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