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ddd [48]
3 years ago
10

Write a polynomial of degree 3 whose only roots are x=2 and x=2/5. Is there another polynomial of degree 3 that has the same roo

ts?
Mathematics
2 answers:
TEA [102]3 years ago
7 0
One such polynomial might be

(x-2)\left(x-\dfrac25\right)^2

Another with the same roots would be

(x-2)^2\left(x-\dfrac25\right)
Allushta [10]3 years ago
5 0

Answer:  The answer is 5x^3-22x^2+28x-8 and 25x^3-70x^244x-8.

Step-by-step explanation:  We are given to write a polynomial of degree 3 whose only roots are 2 and \dfrac{2}{5}. Also, we need to find another polynomial of degree 3, if exists, that has the same roots.

The polynomial will be given by

p(x)=(x-2)(x-2)(x-\dfrac{2}{5})\\\\\Rightarrow 5p(x)=(x^2-4x+4)(5x-2)\\\\\Rightarrow P(x)=5x^3-20x^2+20x-2x^2+8x-8\\\\\Rightarrow P(x)=5x^3-22x^2+28x-8.

The other polynomial with same roots exist and is given by

q(x)=(x-2)(x-\dfrac{2}{5})(x-\dfrac{2}{5})\\\\\Rightarrow 25q(x)=(x-2)(5x-2)^2\\\\\Rightarrow Q(x)=(x-2)(25x^2-20x+4)\\\\\Rightarrow Q(x)=25x^3-20x^2+4x-50x^2+40x-8\\\\\Rightarrow Q(x)=25x^3-70x^244x-8.

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expand vs factor quadratic


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