1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
natka813 [3]
4 years ago
10

How many cups o sauce are needed for 8 servings of spaghetti

Mathematics
2 answers:
enyata [817]4 years ago
5 0

Answer:

4

Step-by-step explanation:

Divided 20÷10 it will equal 2 do it for the rest of the chart and then do 8 divided by 2=4.

Elina [12.6K]4 years ago
4 0

Answer:

It should be 1 cup hope this helped.

Step-by-step explanation:

You might be interested in
A right rectangular prism has edges of 8 feet, 4 feet, and 1/2 foot. How many cubes with side lengths of 1/2 foot would be neede
Ksenya-84 [330]

Answer:

Step-by-step explanation:

From the question we are told that

Edges of 8 feet, 4 feet, and 1/2 foot

Generally the volume V_p of the right rectangular prism is mathematically represented as

V_p=8*4*0.5

V_p=16

Generally volume of the cube V_c is mathematically given as

V_c =(\frac{1}{2})^3

V_c =\frac{1}{6}

Therefore total number of cubes is given as

V=\frac{V_p}{V_c}

V=\frac{16}{\frac{1}{6}}

V=96

4 0
3 years ago
What is the answer to 2/3 of something equals 10
denis23 [38]
In math, when you see the word "of" it usually means "times".

So the question is:

        <u>2/3 times something = 10</u>

Multiply each side of the equation by 3 :

             2 times something = 30

Divide each side by 2 :

                        <em>  something = 15</em>
7 0
4 years ago
Read 2 more answers
Cylinder A is mathematically similar to cylinder B. The height of cylinder A is 10cm and its surface area is 440cm2​ ​. The surf
Pie

Answer:

440 = 2\pi {r}^{2}  + 2\pi(r)10 \\

3960 = 2\pi {r}^{2}  + 2\pi(r)h

\frac{3960 = 2\pi {r}^{2}  + 2\pi(r)h}{440 = 2\pi {r }^{2} + 2\pi(r)10 }

9 =  \frac{h}{10}

h=90

5 0
3 years ago
The distribution of heights of young women aged 18 to 24 is approximately normal with a mean of 64.5 inches and a standard devia
Lena [83]
The 68 - 95 - 99.7 rule, gives the basis to solve this question.

It says that for a normal distribution 95% of the results are between the mean minus 2 standard deviations and the mean plus 2 standard deviations.

Here:
mean = 64.5 inches,
standard deviaton = 2.5 inches

mean - 2 standard deviations = 64.5 inches - 5 inches = 59.5 inches

mean +  2 standard deviations = 64.5 inches + 5 inches = 69.5 inches

Then, the answer is that 95% of women range approximately between 59.5 inches and 69.5 inches.

6 0
4 years ago
You are given that &lt;GHJ is a complement of &lt;RST and &lt;RST is a supplement of &lt;ABC. Let m&lt;GHJ be x°. What is the me
MAVERICK [17]

∠GHJ and ∠RST are complementary

⇒  ∠GHJ and ∠RST = 90°

And ∠RST and ∠ABC are supplementary

⇒  ∠RST and ∠ABC = 180°

Also, ∠GHJ = x°

⇒ ∠RST = 90° - x°

⇒ ∠ABC = 180° - ∠RST

⇒ ∠ABC = 180° - (90° - x°)

⇒ ∠ABC = 90° + x°

6 0
4 years ago
Other questions:
  • Approximate the value of 44 (Square root) to the nearest hundreth
    9·2 answers
  • Elsie, who loves to garden, has the garden plot above. The width of her current garden is 12 the length. Elsie wants to increase
    12·1 answer
  • 3x\2-x=x/6-5/3<br> Solve
    8·2 answers
  • Pls help<br> Pls help<br> Pls help
    10·1 answer
  • given a rectangular has a length of 58.5 m and widht of 45 m. Draw a diagram with scake if givrn scale drawing is 1 cm:9m​
    15·1 answer
  • Help 6th grade math please help i will give brainliest
    10·1 answer
  • Which expression is equivalent to 6y?
    13·1 answer
  • Can u pls help me with this question ​
    10·1 answer
  • What is the equation of the line that is perpendicular to y, =, 1 over 3 x, 4. And contains the point negative 2, negative 5,?.
    8·1 answer
  • What is the image point of (-8, 3) after the transformation R2700 0 T-2,-1?​
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!