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mestny [16]
2 years ago
6

What one is correct?

Chemistry
1 answer:
katen-ka-za [31]2 years ago
7 0

4

Explanation:

I am not positive but it makes more sense

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How many molecules are contained in 0.800 mol o2?
Ksenya-84 [330]
Multiply .800 moles of O2 by Avagadro's number divided by 1 mole. This will get rid of the moles on the bottom and leave you with molecules. So technically .800 times 6.02x10^23.
6 0
2 years ago
How many valence electrons do the halogens possess? group of answer choices
jok3333 [9.3K]

The valence electron does the halogens possess are 7

  • Valence electrons are found in the outermost energy level of an atom
  • They are involved in the formation of chemical bonding with other atoms.
  • The halogens elements are found in group 17 on the periodic table
  • The halogens include fluorine, chlorine, bromine, iodine and astatine.
  • They have seven valence electrons, so they are extremely reactive as they only need one more to fill their outer shell.
  • By octet rule we can say that the electron with 8 outer most shell is full and stable.

Hence the halogens posses 7 valence electron

Learn more about the valence electron on

brainly.com/question/13552988

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5 0
1 year ago
What are the two things that characterize the practice of science
xenn [34]
The two things are hypothesis and empirical evidence
5 0
3 years ago
A metallurgical firm wishes to dispose of 1200 gallons of waste sulfuric acid whose molarity is 1.05 M. Before disposal, it will
Reil [10]

Answer:

The balanced chemical equation for this process:

H_2SO_4(aq)+Ca(OH)_2(s)\rightarrow 2H_2O(l)+CaSO_4(aq)

$194.51 is the cost that the firm will incur from this use of slaked lime.

Explanation:

The balanced chemical equation for this process

H_2SO_4(aq)+Ca(OH)_2(s)\rightarrow 2H_2O(l)+CaSO_4(aq)

Moles of sulfuric acid = n

Volume of sulfuric acid disposed = V = 1200 gallons = 3.785 × 1200 L = 4,542 L

1 gallon = 3.785 Liter

Morality of the sulfuric acid = M = 1.05 m

Molarity(M)=\frac{n}{V(L)}

n=m\times V=1.05 M\times 4,542 L=4,769.1 mol

According to reaction, 1 mol of sulfuric acid reacts with 1 mole of calcium hydroxide.Then 4,769.1 moles of sulfuric acid will recat with ;

\frac{1}{1}\times 4,769.1 mol=4,769.1 mol of calcium hydroxide

Mass of 4,769.1 moles of calcium hydroxide:

4,769.1 mol  74 g/mol = 352,913.4 g

= \frac{352,913.4 }{453.6} pounds =778.03 pounds

(1 pound = 453.6 grams)

Cost of 1 pound of slaked lime  = $0.25

Cost of 778.03 pounds of slaked lime  = $0.25 × 778.03 = $194.51

$194.51 is the cost that the firm will incur from this use of slaked lime.

3 0
3 years ago
At which volume of base added was all the acid neutralized?
Scilla [17]

Answer: The answer is A

im 86% sure

5 0
2 years ago
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