Answer:
B) mostly empty space and has a small, positively charged nucleus
Explanation:
In the gold foil experiment, positively-charged alpha particles were directed towards a gold foil sheet. During the experiment, most of the particles went through the gold foil. However, a select few alpha particles were met with resistance and bounced off the sheet.
This proves that the gold atoms, which made up the gold foil sheet, were mostly empty space as most of the alpha particles passed through it. Furthermore, the particles which bounced off the sheet must have hit small, positively-charged nuclei. The nuclei must have been positive because similar charges repel each other. In other words, if the nuclei were negatively-charged, the positively-charged alpha particles would not bounce off the sheet, but instead "stick" to it.
Answer:
(A) It may be an essentially random process.
Explanation:
The natural folding process of protein can be defective in several human infections and it usually comprises the initial generation of extremely compact state. It may also involve the systematical reduction in the range of conformational species and the initial generation of local structure. Therefore, the only false statement is option (A).
In any redox reaction, the substance that undergoes reduction will 3) <span> gain electrons and have a decrease in oxidation number.</span>
I think the answer you are looking for is .18 moles
Answer:
T2 = 547.2K
Explanation:
Given:
V1 = 135 ml. V2 = 250 ml
T1 = 295.5K. T2 = ?
Using Charles's law and solving for T2,
V1/T1 = V2/T2
T2 = (V2/V1)T1
= (250 ml/135 ml)(295.5K)
= 547.2K (or 273.2°C)
