Answer:82.7% C and 17.3% H
Explanation:
C4 = 12.0107g/mol x 4 = 48.0428 g/mol
H10 = 1.00794 g/mol x 10 = 10.0794 g/mol
Molar Mass of Butane, C4H10 = 48.0428 g/mol + 10.0794 g/mol= 58.1222 g/mol
percent composition of Carbon is = ( mass of carbon contained in butane / molar mass of Butane) x 100
=(48.0428 /58.1222) x 100% = 0.8265 x 100
=82.65% =82.7% of Carbon.
Percent composition of Hydrogen = (mass of Hydrogen contained in Butane / molar mass of Butane )x 100
( 10.0794/58.122 ) x 100% =0.1734 x 100
= 17.3% OF Hydrogen.
Answer:
5.4 tonnes.
Explanation:
The first step is to find the molar mass of Al2O3. Aluminum has a molar mass of about 27 and oxygen has a molar mass of about 16, so 2(27)+3(16)= 102g/mol=0.102kg/mol. 10200kg/0.102kg/mol=100,000 moles of Al2O3 in 10.2 tonnes. Multiplying this by the molar mass of the two aluminums, you get a total of 54*100,000=5400000g=5400kg=5.4 tonnes. Hope this helps!
The reaction for burning of charcoal or complete combustion is as follows:
From the above balanced reaction, 1 mole of carbon releases 1 mole of 
gas.
Converting mass of charcoal into moles as follows:
Molar mass of pure carbon is 12 g/mol thus,
The same moles of is released. Converting these moles into mass as follows:
m=n×M
Molar mass of is 44 g/mol thus,
Converting mass into kg,
Thus, total mass of gas released is 5.5 kg.
All of the above answers are true right answer is option D
because, no bond no molecule no interaction no life,
no bond= only element will exist
Energy would not exist coz energy consumption and excretion takes place during bond formation and bond breaking process!
