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patriot [66]
3 years ago
13

A counselor at a middle school must create an arranged schedule of elective classes for the last 2 periods of the day for all of

the 6th grade students. The counselor has 12 electives courses (e.g. art, band, PE, etc.) to choose from and must select 2 ordered classes for each 6th grade student. How many ways can the counselor arrange the last 2 periods of the day for the 6th grade students?
Mathematics
1 answer:
Vikki [24]3 years ago
7 0

Solution

The counselor has 12 electives courses (e.g. art, band, PE, etc.) to choose from and must select 2 ordered classes for each 6th grade student.

Let S be the sample space.

Then, n(S) = 12C2 = (12 x 11) ÷ (2 x 1 ) =  132 ÷ 2 =  66

Then, n(S) = 12C2 = (12 x 11) ÷ (2 x 1 ) =  132 ÷ 2 =  66

Sixty six (66) ways can the counselor arrange the last 2 periods of the day for the 6th grade students

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7 0
3 years ago
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UkoKoshka [18]
If the gum costs 75 cents today, which is 3 cents less than three times what the pack cost 20 years ago, we just need to arrange what we know into an equation.
We know that the price of gum today is 75 cents, so we can leave that on one side of the equation as a constant. Also, since we are dealing only with cents and not dollars, there is no need to shift the decimal point to the left.

? = 75

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It says that it's 3 cents less than 3 times x. The question is basically the equation in word form.

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Option C is your correct answer.

BTW if we were to solve this, we would see that the old price of a pack of gum is:

3x - 3 = 75
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20 years ago, a 75-cent pack of gum cost 26 cents.
Hope that helped! =)
7 0
4 years ago
Read 2 more answers
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