Answer:
It is pi over nine, the one that your cursor is on. Forgive me if I am wrong
Step-by-step explanation:
Answer:
x = 21
Step-by-step explanation:
To see for what value of x is the equation true, we have to solve x.
![\displaystyle \frac{2}{3} x - 3 = 11\\\\Adding \ 3 \ to \ both \ sides\\\\\frac{2x}{3} = 11 + 3\\\\\frac{2x}{3} = 14\\\\Multiply \ 3 \ to \ both \ sides\\\\2x = 14 \times 3\\\\2x = 42 \\\\Divide\ both\ sides\ by\ 2\\\\x = 42/2\\\\x = 21\\\\For \ x = 21\ the \ given \ equation \ is \ true.\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B2%7D%7B3%7D%20x%20-%203%20%3D%2011%5C%5C%5C%5CAdding%20%5C%203%20%5C%20to%20%5C%20both%20%5C%20sides%5C%5C%5C%5C%5Cfrac%7B2x%7D%7B3%7D%20%3D%2011%20%2B%203%5C%5C%5C%5C%5Cfrac%7B2x%7D%7B3%7D%20%3D%2014%5C%5C%5C%5CMultiply%20%5C%203%20%5C%20to%20%5C%20both%20%5C%20sides%5C%5C%5C%5C2x%20%3D%2014%20%5Ctimes%203%5C%5C%5C%5C2x%20%3D%2042%20%5C%5C%5C%5CDivide%5C%20both%5C%20sides%5C%20by%5C%202%5C%5C%5C%5Cx%20%3D%2042%2F2%5C%5C%5C%5Cx%20%3D%2021%5C%5C%5C%5CFor%20%5C%20x%20%3D%2021%5C%20the%20%5C%20given%20%5C%20equation%20%5C%20is%20%5C%20true.%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3><h3>Peace!</h3>
Answer:
Step-by-step explanation:
2
x
2
+
8
−
4
x
+
3
x
−
6
x
2
+
7
Subtract
6
x
2
from
2
x
2
.
−
4
x
2
+
8
−
4
x
+
3
x
+
7
Add
8
and
7
.
−
4
x
2
−
4
x
+
3
x
+
15
Add
−
4
x
and
3
x
.
−
4
x
2
−
x
+
15
Answer:
a = 15/2
Step-by-step explanation:
3a−15=4a−3a
Combine like terms
3a - 15 = a
Subtract 3a from each side
3a-3a−15=a−3a
-15 = -2a
Divide each side by -2
-15/-2 = -2a/-2
15/2 =a
The value of <em>d</em> is 7.5.
The key to solving equations is doing the inverse, or opposite, function/process.
For example, you subtract when d + 1 = 2:
d + 1 = 2
(d + 1) -1 = (2) - 1
d = 1
In the same way, you add values when you have a negative:
5.5 = -2 + d = d - 2
5.5 = d - 2
(5.5) + 2 = (d - 2) + 2
7.5 = d
Now if instead of adding 2, you subtract 2, the problem becomes:
5.5 = d - 2
(5.5) - 2 = (d - 2) - 2
3.5 = d - 4
This doesn't solve your problem, it just makes the value needed to be canceled out larger.
Thus d = 7.5 and you will add because the value is negative.
