Three hens can lay 3 eggs in 3 days.In how many days can 7 hens lay 7 eggs?
2 answers:
Answer: 3 days
Step-by-step explanation: It would take 3 days for seven hens to 7 lay eggs because each hen lays an egg each day.
1 hen/1 egg = 3 days
7 hens/7 days = 14 eggs
7 hens/3 days = 7 eggs
Answer:
3 days
Step-by-step explanation:
Three hens lay 3 eggs in 3 days
We have to find the days in which 7 hens lay 7 eggs
Hen/egg=
Hen/egg=1
Using unitary method
1 hen lays 1 egg in 3 days
1 hen lays in 1 day =
eggs
7 hens lay 7/3 eggs in 1 day
7 hens lay 1 egg=
days
7 hens lay 7 eggs=
7 hens lay 7 eggs=3 days
Hence, 7 hens lay 7 eggs in 3 days
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Answer:
1. no solutions
2. one solution
Step-by-step explanation:
1. -4(5-3x)=12x+20
-20+12x=12x+20
-40+12x=12x
-40=0?????
So no solutions.
2. 3x+7(x+1)=2(6x+5)+2
3x+7x+7=12x+10+2
10x+7=12x+12
-2x+7=12
-2x=5
x=-5/2
So one solution.
__ 5 __, __
the first would be 2
after 5 is 8
after 8 is 11
Hope this helps!!!
Answer:
Answer is $10,144.50
Step-by-step explanation:
15% of 220 =33
220- 33 = 187
8.5% of 187 =15.89
187+15.89=202.89
202.89 x 50 =10,144.50
It subtracts 2 then adds 5
If she got 5/100 wrong she got 95%
95% is the same as 0.95