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3 years ago

Three hens can lay 3 eggs in 3 days.In how many days can 7 hens lay 7 eggs?

Mathematics

2 answers:

Anna71 [15]3 years ago

6 0

Answer: 3 days

Step-by-step explanation: It would take 3 days for seven hens to 7 lay eggs because each hen lays an egg each day.

1 hen/1 egg = 3 days

7 hens/7 days = 14 eggs

7 hens/3 days = 7 eggs

marin [14]3 years ago

6 0

Answer:

3 days

Step-by-step explanation:

Three hens lay 3 eggs in 3 days

We have to find the days in which 7 hens lay 7 eggs

Hen/egg= $\frac{3}{3}$

Hen/egg=1

Using unitary method

1 hen lays 1 egg in 3 days

1 hen lays in 1 day = $\frac{1}{3}$ eggs

7 hens lay 7/3 eggs in 1 day

7 hens lay 1 egg= $\frac{3}{7}$ days

7 hens lay 7 eggs= $\frac{3}{7}\times 7$

7 hens lay 7 eggs=3 days

Hence, 7 hens lay 7 eggs in 3 days

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3 years ago

-40-8b=-6(1+7b) what’s the answer

Andre45 [30]

$\text{Hey there!}$

$\mathsf{-40-8b=-6(1+7b)}\\\mathsf{SIMPLIFY\ both\ sides\ of\ your\ equation}\\\mathsf{-40-8b=-6(1+7b)}$

$\mathsf{Distribute\ the\ RIGHT\ side\ of\ the\ equation }\\\mathsf{Distribute [the\ formula\ is: a(b+c)=a(b)+a(c)=ab+ac]}\\\mathsf{-6(1)+(-6)}(7b)\\\mathsf{-6(1)=-6}\\\mathsf{-6(7b)=-42b}\\\mathsf{\rightarrow\ =-6+(-42b)}$

$\mathsf{-40-8b=-6+(-42b)}\\\mathsf{\rightarrow -8b-40=-42b-6}$

$\mathsf{ADD\ by\ 42b\ on\ your\ sides}\\\mathsf{-8b-40+42b=-42b-6+42b}\\\mathsf{SOLVE\ above\ correct\ to\ get\ us\ to\ the\ next\ step!}\\\mathsf{\rightarrow 34b-40=-6}$

$\mathsf{ADD\ by\ 40\ on\ your\ sides}\\\mathsf{34b-40+40=-6+40}\\\mathsf{Cancel\ out\ -40+40\ because\ that\ gives\ the\ result\ of\ 0}\\\mathsf{-6+40=34}\\\mathsf{\rightarrow New\ equation: 34b = 34}$

$\mathsf{DIVIDE\ both\ of\ your\ sides\ by\ 34}\\\mathsf{\dfrac{34b}{34}=\dfrac{34}{34}}\\\\\mathsf{Cancel\ out: \dfrac{34b}{34}\ because\ that\ gives\ you\ the\ result\ of\ 1b}\\\\\mathsf{Keep:\dfrac{34}{34}\ because\ it\ solves\ for\ b}\\\\\mathsf{\dfrac{34}{34}=34\div34=1}$