Answer:
A ; 23rd century
Step-by-step explanation:
Here, we want to select which of the options is next to have a descending year.
Since all are in the same century i.e 20-something, we do not have an issue with the first digit.
What we need to work on is the last three digits;
We can have 2210, we can have 2321, we can have 2432, we can also have 2543 and so on.
The most recent of all these is the year 2210, so what century does this belong?
Kindly note that, the years 2001-2100 belong to the 21st century.
The years 2101-2200 belong to the 22nd century while the years 2201-2300 belong to the 23rd century
The year we are looking to place is the year 2201 and thus belongs to between 2201-2300 which is the 23rd century
Answer:
2000? ... assume $2000
Resale Value = $2000*(1 - 0.25)t/yr
where: t = number of year after purchase
at t = 3 yr
Resale Value = $2000*(1 - 0.25)3 = $843.75
checking: at t = 0 $2000 (purchase price)
at t = 1 yr $2000 - 0.25*$2000 = $2000 - $500 = $1500
at t = 2 yr $1500 - 0.25*$1500 = $1500 - $375 = $1125
at t = 3 yr $1125 - 0.25*$1125 = $1125 - $281.25 = $843.75
There is no solution ,<span>a+c=-10;b-c=15;a-2b+c=-5 </span>No solution System of Linear Equations entered : [1] 2a+c=-10
[2] b-c=15
[3] a-2b+c=-5
Equations Simplified or Rearranged :<span><span> [1] 2a + c = -10
</span><span> [2] - c + b = 15
</span><span> [3] a + c - 2b = -5
</span></span>Solve by Substitution :
// Solve equation [3] for the variable c
<span> [3] c = -a + 2b - 5
</span>
// Plug this in for variable c in equation [1]
<span><span> [1] 2a + (-a +2?-5) = -10
</span><span> [1] a = -5
</span></span>
// Plug this in for variable c in equation [2]
<span><span> [2] - (-? +2b-5) + b = 15
</span><span> [2] - b = 10
</span></span>
// Solve equation [2] for the variable ?
<span> [2] ? = b + 10
</span>
// Plug this in for variable ? in equation [1]
<span><span> [1] (? +10) = -5
</span><span> [1] 0 = -15 => NO solution
</span></span><span>No solution</span>
