The number of DVDs that will be checked out for every 100 patrons will be 20.
<h3>How to find that a given condition can be modeled by binomial distribution?</h3>
Binomial distributions consist of n independent Bernoulli trials.
Bernoulli trials are those trials that end up randomly either on success (with probability p) or on failures( with probability 1- p = q (say))
Suppose we have random variable X pertaining to a binomial distribution with parameters n and p, then it is written as
The probability that out of n trials, there'd be x successes is given by
The expected value of X will be:
The information is given in the table.
The probability of getting DVDs will be
The value of n is 100.
Then the number of DVDs that will be checked out for every 100 patrons will be
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Answer:
In the sample, 61% chose wooden chairs (4% less than that claimed by the company), 24.2% chose plastic chairs (4.2% more than that claimed by the company), and 14.8 % chose metal chairs (0.2% less than what the company claimed). Therefore, given that these are differences of less than 5%, we can affirm that these samples are consistent with what the company said.
Step-by-step explanation:
Given that a large furniture company claims that 65% of all individuals who buy chairs from its stores choose wood chairs, 20% choose plastic chairs, and 15% choose metal chairs, and to investigate this claim researchers collected data from a random sample of the companys customers, whose results were 305 wood, 121 plastic, and 74 metal, to determine if the data from the sample consistent with the companys claim the following calculations should be performed:
305 + 121 + 74 = 500
500 = 100
305 = X
305 x 100/500 = X
30,500 / 500 = X
61 = X
500 = 100
121 = X
121 x 100/500 = X
12,100 / 500 = X
24.2 = X
100 - 61 - 24.2 = X
39 - 24.2 = X
14.8 = X
Therefore, in the sample, 61% chose wooden chairs (4% less than that claimed by the company), 24.2% chose plastic chairs (4.2% more than that claimed by the company), and 14.8 % chose metal chairs (0.2% less than what the company claimed). Therefore, given that these are differences of less than 5%, we can affirm that these are samples that are consistent with what the company said.
If one number is 8/15, you take the difference which 7/15.
The answer is
<span>
The IQR is the best measure of variability because the distribution has an outlier.
Hoped I Helped I did the test</span>
Answer:(x, y) ⟶ (x + 4, y + 2)
Step-by-step explanation:
