This is an example of conditional probability because we are trying to find the probability of an event occurring GIVEN the occurrence of some other event. There is a formula for this (see image attached).
If we follow this formula, the numerator would be the probability of (A AND B) which in this case is "48% of the class passed BOTH exams." The denominator in the formula would be that "60% of the class passed ONLY THE SECOND exam."
Therefore, P(A and B) = 0.48, which is 48% expressed as a decimal and P(B)= 0.60, which is 60% expressed as a decimal. Then, you can figure out the answer by dividing.
Answer:
The margin of error will be "0.65". A further explanation is provided below.
Step-by-step explanation:
The given values are:
n = 343
x = 110
At 99% confidence level,
%


then,


or,


Now,
The point estimate will be:
⇒ 
⇒ 
⇒ 
or,
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⇒
The margin of error will be:
⇒ 
On substituting the above values, we get
⇒ 
⇒ 
⇒ 
hence,
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⇒ 
⇒ 
Answer:
1.5 cookies if 2/8 is like 2 cookies out of 8, 1/16 if its like 2/8 of a cookie
Step-by-step explanation: \
1.5: 2 x 3/4 (already ate 1/4) = 1.5
1/16= 1/4 (2/8 reduced) x 1/4