The vertex of a quadratic occurs when the velocity, dy/dx=0.
dy/dx=2x+8, so dy/dx=0 only when:
2x+8=0
2x=-8
x=-4, now you find the y coordinate which is:
y(-4)=(-4)^2+8(-4)+12
y(-4)=16-32+12
y(-4)=-4 so the vertex is at the point:
(-4,-4)
Answer:
5x-1
Step-by-step explanation:
8x-3(x+1)-4
{open the brackets}3x-3
8x-3x-3-4
5x+(-7), which is 5x-7
That's a hard one. I'm trying to figure it out
√52 square root of 52, 6*6=36 -4*-4=16 add them together and then square root that number
Answer:
—1=<x<-3
Since
X<-3
X>=-1
Not shaded means including.