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4 years ago

Is the inequality always, sometimes, or never true? 3x - 14 < 3(x-5)

Mathematics

1 answer:

lys-0071 [83]4 years ago

8 0

Answer:

3x - 14 < 3x - 15

-14 < -15

never true

Step-by-step explanation:

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Number Lines / Algebra. Can anyone please tell me to answers to all of these number lines below. Thank you!!

iren [92.7K]

I will do the first-two lines only.

-4 -3 -2 -1 0 1 2 3 4 5 6

Next line below.

-5 -4 -3 -2 -1 0 1 2 3 4 5

Do the rest.

5 0

3 years ago

If f(x) =ax+b ,f(-3)=-4 and f(3)=2, find the value of a and b please help

hichkok12 [17]

Answer:

a = 1

b = -1

Step-by-step explanation:

First, let's make equations out of those given f(x)'s

-4 = -3a + b

2 = 3a + b

We can use elimination method to get rid of the a real quick

-4 = b

2 = b

Add those together

-2 = 2b

Divide both sides by 2

-2/2 = 2b/2

b = -1

Plug in the new b in one of the original equations; I'm gonna use the bottom one

2 = 3a - 1

+ 1 + 1

3 = 3a

3/3 = 3a/3

a = 1

4 0

2 years ago

ron walks 0.5 mile on track on the track in 10 minutes. stevie walks 0.25 mile on the track in 6 minutes. find the unit rate for

guapka [62]

Ron walks 1/2 mile in 10 minutes. There are six 10 minute intervals in an hour 60 divided by 10 is 6. So, therefore he can walk 1 mile in 20 minutes, 1/3 of an hour and a total of 3 miles per hour.
3 x 20 = 60.

Stevie walks 1/4 of a mile in 6 minutes, so that's 12 minutes to walk 1/2 mile. 60/12=5
Stevie can walk 5 half miles which transfers to 2 1/2 miles per hour.

8 0

3 years ago

Solve the porportion using cross products 18/20=k/110

adoni [48]

18/20=K/110
20K= 110*18
20K= 1980
K= 99

4 0

3 years ago

The first three steps in determining the solution set of the system of equations algebraically are shown in the table. y = −x2 +

lianna [129]

You have a system of equations $\left \{ {{y = -x^2+2x-9} \atop {y =-6x+6}} \right.$ .

1. Substitude right side of second equation into the left side of the first equation: $-6x+6=-x^2+2x-9$ .

2. Solve this equation:
$x^2-2x+9-6x+6=0, \\ x^2-8x+15=0, \\ D=(-8)^2-4\cdot 1\cdot 15=64-60=4, \\ \sqrt{D}=2, \\ x_{1,2}=\dfrac{8\pm 2}{2 } =3,5$ .

3. Find y:
for $x_1=3, y_1=-6\cdot 3+6=-18+6=-12$ ,
for $x_2=5, y_2=-6\cdot 5+6=-30+6=-24$ .

4. The solutions of the system are: (3,-12) and (5,-24).
Answer: Correct choice is A.

7 0

3 years ago

Read 2 more answers