All categories

3 years ago

How many solutions does s^2 -35=-35 have

Mathematics

2 answers:

oksian1 [2.3K]3 years ago

5 0

Answer:

one solution since 0 has no positive or negative.

Step-by-step explanation:

s² - 35 = -35

s² = 0

s = 0

ONE answer

Alexandra [31]3 years ago

4 0

Answer:

1 solution

Step-by-step explanation:

s² - 35 = -35

Add 35 to both sides: s² = 0

s can only be 0, and 0 has no positives nor negatives, so one number.

You might be interested in

4. Find the standard from of the equation of a hyperbola whose foci are (-1,2), (5,2) and its vertices are end points of the dia

Ad libitum [116K]

The standard form of the equation of the hyperbola that satisfies all conditions is (x - 2)²/4 - (y - 2)²/5 = 1 .

<h3>How to find the standard equation of a hyperbola</h3>

In this problem we must determine the equation of the hyperbola in its standard form from the coordinates of the foci and a general equation of a circle. Based on the location of the foci, we see that the axis of symmetry of the hyperbola is parallel to the x-axis. Besides, the center of the hyperbola is the midpoint of the line segment with the foci as endpoints:

(h, k) = 0.5 · (- 1, 2) + 0.5 · (5, 2)

(h, k) = (2, 2)

To determine whether it is possible that the vertices are endpoints of the diameter of the circle, we proceed to modify the general equation of the circle into its standard form.

If the vertices of the hyperbola are endpoints of the diameter of the circle, then the center of the circle must be the midpoint of the line segment. By algebra we find that:

x² + y² - 4 · x - 4 · y + 4= 0

(x² - 4 · x + 4) + (y² - 4 · y + 4) = 4

(x - 2)² + (y - 2)² = 2²

The center of the circle is the midpoint of the line segment. Now we proceed to determine the vertices of the hyperbola:

V₁(x, y) = (0, 2), V₂(x, y) = (4, 2)

And the distance from the center to any of the vertices is 2 (semi-major distance, a) and the semi-minor distance is:

b = √(c² - a²)

b = √(3² - 2²)

b = √5

Therefore, the standard form of the equation of the hyperbola that satisfies all conditions is (x - 2)²/4 - (y - 2)²/5 = 1 .

To learn more on hyperbolae: brainly.com/question/27799190

#SPJ1

5 0

2 years ago

I need some heckin help cuz i suck at math :)

vladimir1956 [14]

Answer:

Step-by-step explanation:

Reasons

2. If two lines are parallel, their corresponding angles are congruent.

3. Congruent angles are equal... Why do they even have this step?

4. A straight line forms a linear pair.

5. Angles in a linear pair are supplementary.

6. ∠1 is supplementary to ∠3. Reason: If an angle is congruent to an angle that is supplementary to a third angle, the first and third angles are congruent OR Transitive Property.

7 0

3 years ago

Nancy also has a mirror that measures 20.32 centimeters long. What is the length of Nancy’s mirror in inches?

tino4ka555 [31]

Answer:

C: 8.00

Step-by-step explanation:

1 in = 2.54 cm

l = 20.32 × 1/2.54

l = 8.00 in

The length of Nancy’s mirror is 8.00 in.

3 0

3 years ago

Use the rational zeroes theorem to state all the possible zeroes of the following polynomial:

Mkey [24]

Answer:

All the possible zeroes of the polynomial: f(x) = $3x^{6} + 4x^{3} - 2x^{2} +4$ are ±1 , ±2 , ±4 , ± $\frac{1}{3}$ , ± $\frac{2}{3}$ , ± $\frac{4}{3}$ by using rational zeroes theorem.

Step-by-step explanation:

Rational zeroes theorem gives the possible roots of polynomial f(x) by taking ratio of p and q where p is a factor of constant term and q is a factor of the leading coefficient.

The polynomial f(x) = $3x^{6} + 4x^{3} - 2x^{2} +4$

Find all factors (p) of the constant term.

Here we are looking for the factors of 4, which are:

±1 , ±2 and ±4

Now find all factors (q) of the coefficient of the leading term

we are looking for the factors of 3, which are:

±1 and ±3

List all possible combinations of ± $\frac{p}{q}$ as the possible zeros of the polynomial.

Thus, we have ±1 , ±2 , ±4 , ± $\frac{1}{3}$ , ± $\frac{2}{3}$ , ± $\frac{4}{3}$ as the possible zeros of the polynomial

Simplify the list to remove and repeated elements.

All the possible zeroes of the polynomial: f(x) = $3x^{6} + 4x^{3} - 2x^{2} +4$ are ±1 , ±2 , ±4 , ± $\frac{1}{3}$ , ± $\frac{2}{3}$ , ± $\frac{4}{3}$

Learn more about Rational zeroes theorem here -https://brainly.ph/question/24649641

#SPJ10

7 0

2 years ago

AB GAME

Lesechka [4]

A is the correct answer to this problem

7 0

3 years ago

Read 2 more answers

How many solutions does s^2 -35=-35 have​

How many solutions does s^2 -35=-35 have