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4 years ago

I don't get this pls help

Mathematics

1 answer:

dmitriy555 [2]4 years ago

3 0

Answer:

d, e

Step-by-step explanation:

The applicable rules of exponents are ...

(a^b)(a^c) = a^(b+c)

a^-b = 1/a^b

In this case, it means the product is ...

(6^1)(6^0)(6^-3) = 6^(1+0-3) = 6^-2 = 1/6^2 = 1/36

The 6 without an exponent is equivalent to 6^1, an exponent of 1.

The sum of the exponents is -2.

Add the exponents to simplify the expression.

The value of the expression is 1/36.

An equivalent is any expression that results in 6^-2. One such is (6^5)(6^-7).

Only the last two choices, d and e, apply.

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3 years ago

Suppose that the inverse demand for a downstream firm is P = 150 − Q. Its upstream division produces a critical input with costs

kozerog [31]

Answer:

The marginal revenue is $MT_d = 116.66$

Step-by-step explanation:

From the question we are told that

The inverse demand for a downstream firm is $P = 150 -Q$

The cost of the critical input produced by upstream division is $CU(Q_d) = 5(Q_d)^2$

The cost of the critical input produced by downstream firm is Cd(Q) = 10Q

Generally

The marginal revenue of the downstream firm - The marginal cost of the downstream firm = Net marginal revenue of downstream

i.e

$MR_d - MC_d = MT_d$

Also

The marginal revenue of the downstream firm - The marginal cost of the downstream firm = Marginal upstream cost

i.e

$MR_d - MC_d = MC_u$

Generally the total revenue of downstream firm is mathematically represented as

$TR = P * Q$

Here Q stands for quantity produced by the downstream firm and TR is the total revenue

$TR = [150 - Q] * Q$

=> $TR = 150Q - Q^2$

Generally the marginal revenue of the downstream firm is mathematically evaluated as

$MR_d =\frac{d (TR)}{d Q} = 150 - 2Q$

Generally marginal downstream first cost is mathematically evaluated as

$MC_d = \frac{d(Cd(Q)) }{dQ} = 10$

Generally the net marginal revenue of the downstream firm is mathematically represented as

$150 - 2Q -10 = MT_d$

=> $MT_d = 140 - 2Q$

Generally the marginal upstream cost is mathematically represented a

$MC _u =\frac{d [CU(Q_d)]}{dQ_d} = 10(Q_d)$

Generally $Q_d = Q$ this because $Q_d$ represents the quantity produced by the downstream firm and also Q is associated with the cost of the downstream quantity

$MC _u =\frac{d [CU(Q)]}{dQ} = 10Q$

=> $10(Q) = 140 -2Q$

=> $Q = 11.67$

So the net marginal revenue of the downstream firm is mathematically represented as

=> $MT_d = 140 - 2(11.67)$

=> $MT_d = 116.66$

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3 years ago