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Zigmanuir [339]
4 years ago
6

Find the volume of the prism. Write the answer as a fraction in simplest form.

Mathematics
1 answer:
valina [46]4 years ago
7 0

Answer:1 1/4

Step-by-step explanation:

if u add all together in decimals it will become 1.125.

pls give me brainless

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Where is the function f(x)=3x^2-6x-45/x^2-5x discontinuous, and what types of discontinuities does it have?
Vedmedyk [2.9K]

Answer:

Below.

Step-by-step explanation:

f(x)=3x^2-6x-45/x^2-5x

= 3x^2-6x-45 / (x(x - 5))

The denominator is zero when x - 0 and x = 5.

So there will be a vertical asymptote  at x = 0 and a hole at x = 5.

If we do the division  we get f(x)  = 3  remainder 9x - 45

so there will also be a horizontal asymptote where x = 3.

5 0
3 years ago
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Recall that m(t) = (1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500g sample of phosphorus-32 decays
katrin2010 [14]

The question is incomplete, here is the complete question:

Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.

<u>Answer:</u> The half life of the sample of phosphorus-32 is 14.28days^{-1}

<u>Step-by-step explanation:</u>

The equation used to calculate the half life of the sample is given as:

m(t)=m_o(1/2)^{t/h}

where,

m(t) =  amount of sample after time 't' = 356 g

m_o = initial amount of the sample = 500 g

t = time period = 7 days

h = half life of the sample = ?

Putting values in above equation, we get:

356=500\times (\frac{1}{2})^{7/h}\\\\h=14.28days^{-1}

Hence, the half life of the sample of phosphorus-32 is 14.28days^{-1}

7 0
4 years ago
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vitfil [10]

Answer:

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3 years ago
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Answer:

d..

Step-by-step explanation:

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What is 2.006 in expended form
Verizon [17]
2+ 0.0 + 0.00 + .006
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