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3 years ago

Please help pre Algebra question

Mathematics

1 answer:

qaws [65]3 years ago

5 0

Answer:

4=No

-3=No

2=Yes

0=No

Step-by-step explanation:

enter enter all the factors into the equation and see which one equals -28 on both sides at the end.

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What is the value of x in the equation (x + 12) = (x + 14) – 3?

vodomira [7]

(x + 12) = (x + 14) - 3

subtract 12 from each side

x = x + 14 - 3 - 12

Now if we subtract x from each side we see that x - x = 0. Combine the terms left over and we have -1, so

0 = -1

The answer is NO SOLUTION

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3 years ago

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What are the solution(s) of –x2 + 2x + 3 = x2 – 2x + 3?

Leviafan [203]

-x^2+2x+3=x^2-2x+3 add x^2 to both sides

2x+3=2x^2-2x+3 subtract 2x from both sides

3=2x^2-4x+3 subtract 3 from both sides

2x^2-4x=0 factor

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So x=0 and 2

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3 years ago

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PLZ HELPPPP !!!

Blizzard [7]

Answer:

Step-by-step explanation:

Calculate the volume of a cone by its base and height with the equation volume = 1/3 * base * height. You can calculate the height of a cone from its volume by reversing this equation. Triple the volume amount. For this example, the volume is 100.

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3 years ago

Hi can you help !!!???

GalinKa [24]

Answer:

Step-by-step explanation:

4 1/3 can be separated into 4, and 1/3.

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2 years ago

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Find the laplace transform of f(t) = cosh kt = (e kt + e −kt)/2

iren2701 [21]

Hello there, hope I can help!

I assume you mean $L\left\{\frac{ekt+e-kt}{2}\right\}$
With that, let's begin

$\frac{ekt+e-kt}{2}=\frac{ekt}{2}+\frac{e}{2}-\frac{kt}{2} \ \textgreater \ L\left\{\frac{ekt}{2}-\frac{kt}{2}+\frac{e}{2}\right\}$

$\mathrm{Use\:the\:linearity\:property\:of\:Laplace\:Transform}$
$\mathrm{For\:functions\:}f\left(t\right),\:g\left(t\right)\mathrm{\:and\:constants\:}a,\:b$
$L\left\{a\cdot f\left(t\right)+b\cdot g\left(t\right)\right\}=a\cdot L\left\{f\left(t\right)\right\}+b\cdot L\left\{g\left(t\right)\right\}$
$\frac{ek}{2}L\left\{t\right\}+L\left\{\frac{e}{2}\right\}-\frac{k}{2}L\left\{t\right\}$

$L\left\{t\right\} \ \textgreater \ \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{t\right\}=\frac{1}{s^2} \ \textgreater \ L\left\{t\right\}=\frac{1}{s^2}$

$L\left\{\frac{e}{2}\right\} \ \textgreater \ \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{a\right\}=\frac{a}{s} \ \textgreater \ L\left\{\frac{e}{2}\right\}=\frac{\frac{e}{2}}{s} \ \textgreater \ \frac{e}{2s}$

$\frac{ek}{2}\cdot \frac{1}{s^2}+\frac{e}{2s}-\frac{k}{2}\cdot \frac{1}{s^2}$

$\frac{ek}{2}\cdot \frac{1}{s^2} \ \textgreater \ \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \ \frac{ek\cdot \:1}{2s^2} \ \textgreater \ \mathrm{Apply\:rule}\:1\cdot \:a=a$
$\frac{ek}{2s^2}$

$\frac{k}{2}\cdot \frac{1}{s^2} \ \textgreater \ \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \ \frac{k\cdot \:1}{2s^2} \ \textgreater \ \mathrm{Apply\:rule}\:1\cdot \:a=a$
$\frac{k}{2s^2}$

$\frac{ek}{2s^2}+\frac{e}{2s}-\frac{k}{2s^2}$

Hope this helps!

3 0

3 years ago