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Svetllana [295]
4 years ago
12

Vincent combines sodium and chlorine in two different beakers (beaker X and beaker Y). In both beakers, the chemical reaction sh

own below occurs.
Chemistry
1 answer:
svlad2 [7]4 years ago
4 0

Answer: the chemical change will occur faster in beaker X.

Explanation:

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2. As the sun heats the surface of the oceans, two layers of water result. What separates the layers?
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Carbon dioxide I think lol
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At which temperature will the least amount of time pass before someone detects the odor of a fragrant flower?
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0C, 8C, 29C, 15C. I think 
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4 years ago
If an automobile air bag has a volume of 11.6 ll , what mass of nan3nan3 (in gg ) is required to fully inflate the air bag upon
Tresset [83]

22.3 g of NaN₃ are required to fully inflate an airbag of 11.6 L at STP.

To find the mass, the given data was,

Volume = 11.6 Liters

<h3>What is decomposition reaction?</h3>

A decomposition reaction can be defined as a chemical reaction in which one reactant breaks down into two or more products.

In airbags, sodium azide decomposes to form sodium and nitrogen gas, which inflates the bag. The decomposition reaction is:

2 NaN₃ ⇒ 2 Na + 3 N₂

We can calculate the mass of NaN₃ needed to produce 11.6 L of N₂ at STP, using the following relations.

  • At STP, 1 mole of N₂ occupies 22.4 L.
  • The molar ratio of N₂ to NaN₃ is 3:2.
  • The molar mass of NaN₃ is 65.01 g/mol.

Substituting all the known values to find the volume,

11.6 × ( 1 / 22.4) × ( 2/3) × ( 65.01 / 1)

= 22.4 g.

22.4 g of NaN₃ are required to fully inflate an airbag of 11.6 L at STP.

Learn more about decomposition reaction,

brainly.com/question/8009068

#SPJ4

5 0
2 years ago
Nitrogen dioxide is used industrially to produce nitric acid, but it contributes to acid rain and photochemical smog. What volum
Strike441 [17]

Answer:

35.41 L

Explanation:

Given, Volume of Copper = 4.84 cm³

Density = 8.95 g/cm³

Considering the expression for density as:

Density=\frac {Mass}{Volume}

So,

So, Mass= Density  Volume = 8.95 g/cm³  4.84 cm³ = 43.318 g

Mass of copper = 43.318 g

Molar mass of copper = 63.546 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{43.318\ g}{63.546\ g/mol}

Moles of copper = 0.6817 moles

Given, Volume of nitric acid solution = 227 mL = 227 cm³

Density = 1.42 g/cm³

Considering the expression for density as:

Density=\frac {Mass}{Volume}

So,

So, Mass= Density  Volume = 1.42 g/cm³  227 cm³ = 322.34 g

Also, Nitric acid is 68.0 % by mass. So,  

Mass of nitric acid = \frac {68}{100}\times 322.34\ g = 219.1912 g

Molar mass of nitric acid = 63.01 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{219.1912\ g}{63.01\ g/mol}

Moles of nitric acid = 3.4786 moles

According to the reaction,  

Cu_{(s)}+4HNO_3_{(aq)}\rightarrow Cu(NO_3)_2_{(aq)} + 2NO_2_{(g)} + 2H_2O_{(l)}

1 mole of copper react with 4 moles of nitric acid

Thus,  

0.6817 moles of copper react with 4*0.6817 moles of nitric acid

Moles of nitric acid required = 2.7268 moles

Available moles of nitric acid = 3.4786 moles

Limiting reagent is the one which is present in small amount. Thus, nitric acid is present in large amount, copper is the limiting reagent.

The formation of the product is governed by the limiting reagent. So,

1 mole of copper on reaction forms 2 moles of nitrogen dioxide

So,

0.6817 mole of copper on reaction forms 2*0.6817 moles of nitrogen dioxide

Moles of nitrogen dioxide = 1.3634 moles

Given:  

Pressure = 724 torr

The conversion of P(torr) to P(atm) is shown below:

P(torr)=\frac {1}{760}\times P(atm)

So,  

Pressure = 724 / 760 atm = 0.9526 atm

Temperature = 28.2 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (28.2 + 273.15) K = 301.35 K  

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

0.9526 atm × V = 1.3634 mol × 0.0821 L.atm/K.mol × 301.35 K  

⇒V = 35.41 L

3 0
3 years ago
What word or two-word phrase best describes the shape of the hydrogen cyanide ( hcn ) molecule?
elena-14-01-66 [18.8K]

Answer : Linear

Explanation : Hydrogen Cyanide (HCN) when drwan in the Lewis diagram shows carbon atom at the center with no lone electron pairs.

The carbon and nitrogen atoms are bonded through a triple bond which counts as "one electron pair".

The molecule has two electron pairs in all and appears to be linear.

Also, according to the VSEPR theory; the electron clouds on atoms around the carbon will try to repel each other.

They will get pushed apart, which gives HCN molecule a linear molecular geometry or shape.

The bond angle that is developed will be 180 degrees since it has a linear molecular geometry of HCN. The hybridisation observed in this molecule is SP.

5 0
4 years ago
Read 2 more answers
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