5 ml=5 cm³ , density=mass/volume=45/5= 9 g/cm³ therefore answer B
Answer:
237.5 K.
Explanation:
- We can use the general law of ideal gas: <em>PV = nRT.
</em>
where, P is the pressure of the gas in atm (P = 5.2 atm).
V is the volume of the gas in L (V = 15.0 L).
n is the no. of moles of the gas in mol (n = 4.0 mol).
R is the general gas constant (R = 0.0821 L.atm/mol.K),
T is the temperature of the gas in K (T = ??? K).
∴ T = PV/nR = (5.2 atm)(15.0 L)/(4.0 mol)(0.0821 L.atm/mol.K) = 237.5 K.
The weight will decrease because more solute (osmosis) on the outside.
Decrease and Outside is the answer
