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3 years ago

01:48:21

Chemistry

1 answer:

Aleonysh [2.5K]3 years ago

5 0

Answer:

It is 12.00 g of carbon-12.

Explanation:

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3 points

vfiekz [6]

Answer:

density=6.74g/ml

:320g÷47.5ml

d=6.74g/ml

thank you

I hope this is helpful

8 0

3 years ago

The absorbance of a cationic iron(II) sample solution was measured in a spectrophotometer, but the instrument returned an error

JulijaS [17]

Answer:

$1.35\times 10^{-4} M$ was the concentration of the original solution.

Explanation:

$M_1V_1=M_2V_2$ (Dilution)

where,

$M_1\text{ and }V_1$ are molarity and volume of non diluted sample.

$M_2\text{ and }V_2$ are molarity and volume of diluted sample.

$M_1=?$

$V_1=100.0 \mu L=0.1 mL$

(1μL=0.001 mL)

$M_2=6.41\times 10^{-6} M$

$V_2=2.00 mL + 100.0 \mu L=2.00 mL+0.1 mL=2.1 mL$

Substituting all values :

$M_1\times 0.1 mL=6.41\times 10^{-6} M\times 2.1 mL$

$M_1=\frac{6.41\times 10^{-6} M\times 2.1 mL}{0.1 mL}=1.35\times 10^{-4} M$

$1.35\times 10^{-4} M$ was the concentration of the original solution.

5 0

3 years ago

You have 363 mL of a 1.25M potassium chloride solution, but you need to make a 0.50M potassium chloride solution. How many milli

maxonik [38]

Answer:- 544.5 mL of water need to be added.

Solution:- It is a dilution problem. The equation used for solving this type of problems is:

$M_1V_1=M_2V_2$

where, $M_1$ is initial molarity and $M_2$ is the molarity after dilution. Similarly, $V_1$ is the volume before dilution and $V_2$ is the volume after dilution.

Let's plug in the values in the equation:

$1.25M(363mL)=0.50M(V_2)$

$V_2=\frac{1.25M(363mL)}{0.50M}$

$V_2=907.5mL$

Volume of water added = 907.5mL - 363mL = 544.5 mL

So, 544.5 mL of water are need to be added to the original solution for dilution.

3 0

3 years ago

How many seconds in the school year? (One school year is 180 days long.) Please show your work, and report your answer with the

Masja [62]

Answer:

259200

Explanation:

multiply 180×24×60

259,200 seconds

8 0

3 years ago

Read 2 more answers

Please help me with this question please!!!

Deffense [45]

Answer:

Explanation:

I looked up aromatic hydrocarbon and this one looks like a replica of benzene

3 0

3 years ago