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3 years ago

Can someone help me with this?

Mathematics

1 answer:

mr Goodwill [35]3 years ago

7 0

If you look closely you'll see that x can take on any real value here. On the other hand, y can equal -4 (maximum) or any real number smaller than -4.
Translate this information into interval notation.

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PLEASE HELP! :) IMAGE IS BELOW!! QUESTION: Describe a series of transformations that will transform ∆ABC to ∆A'B'C'.

Aliun [14]

Answer:

Dilation and translation.

Hope that helps!

Step-by-step explanation:

7 0

3 years ago

Thu wants to play “Guess My Number,"she states. “When I triple my number and add five ,I get twenty-six.what is my number?" What

AleksandrR [38]

The correct answer is:

Her number is 7.

Explanation:

Let x represent her number.

She triples her number; this is represented by 3x.

She then adds 5 to this; this gives us 3x+5.

She gets 26 aas her answer. This gives us the equation:

3x+5 = 26

To solve this, first subtract 5 from each side:

3x+5-5 = 26-5

3x = 21

Divide each side by 3:

3x/3 = 21/3

x = 7

5 0

3 years ago

Read 2 more answers

What is the factored or of 25y^4 - 4z^2

Cerrena [4.2K]

Answer:

$(5y^2+2z)(5y^2-2z)$

Step-by-step explanation:

Use the difference of squares formula.

$a^2-b^2=(a+b)(a-b)$

$a=5y^2 \\ b=2z$

$(5y^2+2z)(5y^2-2z)$

5 0

3 years ago

The equations in the triangle consist of (2x +1) and (5x +5)

Ainat [17]

2x + 1 + 5x + 5 + 90 = 180
7x + 96 = 180
7x = 180 - 96
7x = 84
x = 12

6 0

3 years ago

Wanni cycled 6 km from her house to the school at a uniform speed, v km/h. If she increased her speed

Karolina [17]

Answer:

The quadratic equation in terms of v is v² + 2 v + 180 = 0

Step-by-step explanation:

Given as :

The distance between house to the school = d = 6 km

The uniform speed = v km/h

So, Time = $\dfrac{\textrm Distance}{\textrm speed}$

or, t = $\dfrac{\textrm d}{\textrm v}$

Or, t = $\dfrac{\textrm 6}{\textrm v}$

Now, Again

The speed is increase by 2 km/h

i.e speed = (v + 2) km/h

So, Time taken = t' = (t - $\dfrac{4}{60}$ )hours

i.e t' = (t - $\dfrac{1}{15}$ )hours

Now, Time = $\dfrac{\textrm Distance}{\textrm speed}$

So, (t - $\dfrac{1}{15}$ ) = $\dfrac{\textrm d}{\textrm v}$

Or, (t - $\dfrac{1}{15}$ ) = $\dfrac{\textrm 6}{\textrm (v + 2)}$

Or , $\dfrac{\textrm 6}{\textrm v}$ - $\dfrac{1}{15}$ = $\dfrac{\textrm 6}{\textrm (v + 2)}$

Or , $\dfrac{\textrm 90 - v}{\textrm 15 v}$ = $\dfrac{\textrm 6}{\textrm v + 2}$

Or, (90 - v) × (v + 2) = 6 × 15 v

Or, 90 v - 180 - v² - 2 v = 90 v

Or, v² + 2 v + 180 = 90 v - 90 v

Or, v² + 2 v + 180 = 0

So, The quadratic equation in terms of v

v² + 2 v + 180 = 0

Hence The quadratic equation in terms of v is v² + 2 v + 180 = 0 Answer

3 0

3 years ago