First person to answer right gets 40 points

Quadrilateral QRST has two pairs of congruentes sides, but it is not a parallelogram. What figure is it? What further condition

Whitepunk [10]

Answer:

The correct answer is: [C]:

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" {The figure is a kite. To be a parallelogram, it would have to have pairs of opposite congruent sides, not just congruent sides. } ."

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Step-by-step explanation:

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Note that "all" squares are "parallelograms" ; and that "all" rectangles are

"parallelograms" ;

yet: "Not All parallelograms" are "squares" or "rectangles".

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The question asks:

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"Quadrilateral QRST has two pairs of congruent sides, but it is not a parallelogram.

What figure is it?

What further condition would have to satisfy to be a parallelogram? " .

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So; we can rule out:

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"Answer choices:

[A]: "The figure is a square..." ;

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[B]: "The figure is a rectangle..." ; AND :

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[D]: "The figure is a square..." .

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We are left with:

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Answer choice: [C]:

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" { The figure is a kite. To be a parallelogram, it would have to have pairs of opposite congruent sides, not just congruent sides. } " .

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7 0

3 years ago

Factor the expression 3x²-7x+4 completely

jeyben [28]

Answer:

2x+4

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

What's the answer to this?

beks73 [17]

Answer:

Q' = (-4, -2)

R' = (4, -2)

S' = (4, 2)

T' = (-4, 2)

Step-by-step explanation:

First, we can create a matrix to scale this rectangle by putting all the x coordinates in the top row and all the y coordinates in the bottom row and multiply it by 4.

Our initial matrix to multiply:

$4\left[\begin{array}{cccc}-1&1&1&-1\\-2&-2&-1&-1\end{array}\right]$

Moved to the origin:

$4\left[\begin{array}{cccc}-1&1&1&-1\\-0.5&-0.5&0.5&0.5\end{array}\right]$

Multiplied by four:

$\left[\begin{array}{cccc}-4&4&4&-4\\-2&-2&2&2\end{array}\right]$

This gives us the points of

Q' = (-4, -2)

R' = (4, -2)

S' = (4, 2)

T' = (-4, 2)

which are our answers.

3 0

2 years ago

Let X be from a geometric distribution with probability of success p. Given that P(X > y) = (1 ???? p)y for any positive inte

nevsk [136]

Full Question

Let X be from a geometric distribution with probability of success p.

Given that P ( X > a + b | X > a ) = q ^ { b } = P ( X > b ) for any positive integer x.

Show that for positive integers a and b, P(X > a + b | X > a) = P(X > b).

Answer:

P(X > a + b | X > a) = P(X > b)

Proved --- See Explanation

Step-by-step explanation:

Given

P ( X > a + b | X > a ) = q ^ { b } = P ( X > b )

From the above.

We can derive the following

P(X > a), P(X > b) and P(X > a + b)

P(X > a) = q^a

P(X > b) = q^b

P(X > a + b) = q^(a + b)

Using the definition of conditional probability

P(X > a + b | X > a) can be represented by P(X > a + b and X > a)/ P(X>a)

X>a+b and X>a is equivalent to X>a+b since a+b is larger than a

So,

P(X > a + b and X > a)/ P(X>a) can be rewritten as

P(X>a + b)/P(X > a)

Bringing both sides together, we're left with

P(X > a + b | X > a) = P(X>a + b)/P(X > a)

By substituton

P(X > a + b | X > a) = q^(a+b)/q^a

P(X > a + b | X > a) = q^(a + b - a)

P(X > a + b | X > a) = q^(a - a + b)

P(X > a + b | X > a) = q^b

Since P(X > b) = q^b

So,

P(X > a + b | X > a) = P(X > b)

4 0

3 years ago

What is a linear expression?

never [62]

A linear expression is one that has a variable in it. Also, no variable is raised higher than a power of 1 or used as a denominator. So you can't divide by a variable. So if a linear equation is commonly expressed as "y= mx+b", a linear expression would be expressed as mx+b.

4 0

3 years ago