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dmitriy555 [2]
2 years ago
12

The variables x and y are proportional. Use the values to find the constant of proportionality. Then write an equation that rela

tes x and y.
When y=72 and x=3.

K = ?

y = ?
Mathematics
1 answer:
Sidana [21]2 years ago
3 0

Answer:

k = 24, y = 24x

Step-by-step explanation:

Given x and y are proportional then the equation relating them is

y = kx ← k is the constant of variation

To find k use the condition when y = 72, x = 3 , then

72 = 3k ( divide both sides by 3 )

k = 24

y = 24x ← equation of proportion

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What are u asking, sorry.
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3 years ago
Can somebody please help me I will mark u brilliant
givi [52]

Answer:

2/7 + (-3/4) + (-2/7) + 4/3

If we look at 2/7 and (-2/7), we can see that both of them combined will get you a result of 0, so let's do that first.

2/7 + (-2/7) = 0

Now we're left with;

(-3/4) + 4/3

Make sure to convert both fractions into having a common denominator,

[They both have a common denominator of 12], so:

(-3/4) = (-9/<u>12</u>)

4/3 = 16/<u>12</u>

Add them:

(-9/12) + 16/12

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= <u>7/12</u>, which cannot further be simplified.

3 0
1 year ago
My problem is : P=2L+2W solve for L
natima [27]
Answer:
L = P/2 - W

Explanation:
Step 1 - Start by factoring out the two

P = 2L + 2W
P = 2(L + W)

Step 2 - Divide both sides of the equation by two

P = 2(L + W)
P/ 2 = 2(L + W)/ 2
P/ 2 = L + W

Step 3 - Subtract W from both sides of the equation

P/ 2 = L + W
P/ 2 - W = L + W - W
P/ 2 - W = L
3 0
3 years ago
Read 2 more answers
Determine the solution for the equation.
Ilya [14]
Answer:
2^4=16
Hope i helped
6 0
2 years ago
A world record was set for the men’s 100-m dash in the 2008 Olympic Games in Beijing by Usain Bolt of Jamaica. Bolt "coasted" ac
Andrei [34K]

Answer:

a) v = 12.21m/s

a = 4.07 m/s²

b)v = 11.24m/s

a =  3.75 m/s²

Step-by-step explanation:

a) Dividing the moviment into two parts:

I - With acceleration

v = v₀ + at

s = s₀ + v₀t + at²/2

  • v₀ = 0
  • s₀ = 0
  • a = ?
  • v = ?
  • t = 3s
  • s = x

v = v₀ + at

v = 3a ⇒ a = v/3

s = s₀ + v₀t + at²/2

x = v/3.3²/2

x = 3v/2

II - Uniform

s = s₀ + vt

s = 100

s₀ = x

v = v

t = 9.69 - 3 = 6.69s

s = s₀ + vt

100 = x + v*6.69

100 = x + 6.69v

As x = 3v/2

100 = 3v/2 + 6.69v

100 = 1.5v + 6.69v

100 = 8.19v

v = 12.21m/s

a = v/3 = 4.07 m/s²

b) Dividing the moviment into two parts:

I - With acceleration

v = v₀ + at

s = s₀ + v₀t + at²/2

  • v₀ = 0
  • s₀ = 0
  • a = ?
  • v = ?
  • t = 3s
  • s = x

v = v₀ + at

v = 3a ⇒ a = v/3

s = s₀ + v₀t + at²/2

x = v/3.3²/2

x = 3v/2

II - Uniform

s = s₀ + vt

s = 200

s₀ = x

v = v

t = 19.30 - 3 = 16.30s

s = s₀ + vt

200 = x + v*16.3

100 = x + 16.3v

As x = 3v/2

200 = 3v/2 + 16.3v

200 = 1.5v + 16.3v

200 = 17.8v

v = 11.24m/s

a = v/3 = 3.75 m/s²

8 0
2 years ago
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