Answer:
min at (3, 0 )
Step-by-step explanation:
given a quadratic in standard form
y = ax² + bx + c ( a ≠ 0 )
then the x- coordinate of the vertex is
= - 
y = (x - 3)² = x² - 6x + 9 ← in standard form
with a = 1 and b = - 6 , then
= - 
= 3
substitute x = 3 into the equation for corresponding value of y
y = (3 - 3)² = 0² = 0
vertex = (3, 0 )
• if a > 0 then vertex is minimum
• if a < 0 then vertex is maximum
here a = 1 > 0 then (3, 0 ) is a minimum
19/38 and 15/18
Explanation:
19/38 can be reduced as there is a factor other than 1 that can divide without a remainder. Factor is 19
It can still be reduced because 19*2 = 38
19/38 = 1/2
10/19 cannot be reduced as there is no factor other than one to divide without a remainder
21/34 cannot be reduced as there is no factor other than one to divide without a remainder
15/18 can be reduced as there is a factor other than 1 that can divide without a remainder.
The factor is 3
15/18 = 5/6
Fraction that has not been reduced to simplest form are 19/38 and 15/18
Answer:
The sequence is arithmetic with a common difference of -10
Step-by-step explanation:
From the question, we want to determine if the sequence is arithmetic or geometric
From the question
f(1) = 5
f(2) = -5
f(3) = -15
Mathematically for the common difference;
f(3) - f(2) = f(2) - f(1)
Since;
-15-(-5) = -5-5
-10 = -10
Since the common difference here is same , then the sequence is arithmetic with a common difference of -10
