Question

Plzzz Help ASAP! This image shows a square pyramid what is the surface area of this square pyramid?

Answer 1

Answer:

$72\ ft^{2}$

Step-by-step explanation:

we know that

The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces

so

$SA=b^{2}+4[\frac{1}{2}bh]$

where

b is the length side of the square base

h is the height of the triangular face

Remember that

Each lateral triangular face is a triangle 45°-90°-45°

so

$h=b/2$

we have

$b=6\ ft$

so

$h=6/2=3\ ft$

substitute in the formula

$SA=6^{2}+4[\frac{1}{2}(6)(3)]=72\ ft^{2}$